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3 years ago

N is an integer with -5 < 2n <6 write down all the values of n?

Mathematics

1 answer:

Alika [10]3 years ago

7 0

Answer:

The values of n are less than 3 and more than (-5/2)

Step-by-step explanation:

The given inequality is :

-5 < 2n <6

We need to write the values of n.

Dividing both sides of the inequality by 2. So,

$\dfrac{ -5}{2} < \dfrac{2n}{2}$

So, the values of n are less than 3 and more than (-5/2).

You might be interested in

Find the decimals places of .35x9.2

ollegr [7]

Answer:

3.22

Step-by-step explanation:

You would multiply it normally than move one place behind the decimal.

6 0

3 years ago

100 POINTSSS! ASAP ANSWEERR PLS

Margarita [4]

PART A

Given:

f(x) = 0.69(1.03)x

To find:

If the price of the product is increasing or decreasing and by what percentage

Steps:

we know the formula to find the price of Product A per year, so

f(1) = 0.69 * 1.03 * 1

Price = $0.7107

f(2) = 0.69 * 1.03 * 2

Price = $1.4214

Here the Price of Product after 2 years is greater than the price of Product after one year. So the price of the product A is increasing.

Now to find percentage increase,

Percentage increase = $\frac{FV-SV}{SV}*100$ (FV = final value, SV = starting value)

Percentage increase = $\frac{1.4214 - 0.7107}{0.7107}*100$

Percentage increase = $\frac{0.7107}{0.7107}*100$

Percentage increase = 100 %

Therefore, the percentage increase of Product A is 100%

PART B

Given:

Price of product B in 1st year = $10,100

Price of product B in 2nd year = $10,201

Price of product B in 3rd year = $10,303.01

Price of product B in 4th year = $10,406.04

To find:

Which product recorded a greater percentage change over the previous year

Steps:

We need to find the percentage change of Product B and Product A of each year. We know that the percentage change of product A is 100 % for each year, so we only need to calculate for product B

PC of product B from 1st to 2nd year = $\frac{10,201-10,100}{10,100}*100$

= $\frac{101}{10,100}*100$

= 0.01 * 100

= 1 %

PC of product B from 2nd to 3rd year = $\frac{10,303.01-10,201}{10,201} *100$

= 1%

PC of product B from 3rd to 4th year $=\frac{10,406.04-10,303.01}{10,303.01}*100$

≈ 1%

So, percentage change of product B is 1% per year

Therefore, Product A has greater percentage change

Happy to help :)

If u need more help, feel free to ask

6 0

3 years ago

Solve the equation. 3x + 6 = 24

Makovka662 [10]

Answer:

option no.C 6

Step-by-step explanation:

3x+6=24

3x=24–6

3x=18

x=18/3

x=6

7 0

3 years ago

Read 2 more answers

Answer please answer

lutik1710 [3]

Answer:

3= 1680

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

-x^2+50=25 solve the equation

Andru [333]

Answer:

Two solutions were found :

x = 5

x = -5

Step-by-step explanation:

Step 1 :

Trying to factor as a Difference of Squares :

1.1 Factoring: 25-x2

Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)

Proof : (A+B) • (A-B) =

A2 - AB + BA - B2 =

A2 - AB + AB - B2 =

A2 - B2

Note : AB = BA is the commutative property of multiplication.

Note : - AB + AB equals zero and is therefore eliminated from the expression.

Check : 25 is the square of 5

Check : x2 is the square of x1

Factorization is : (5 + x) • (5 - x)

Equation at the end of step 1 :

(x + 5) • (5 - x) = 0

Step 2 :

Theory - Roots of a product :

2.1 A product of several terms equals zero.

When a product of two or more terms equals zero, then at least one of the terms must be zero.

We shall now solve each term = 0 separately

In other words, we are going to solve as many equations as there are terms in the product

Any solution of term = 0 solves product = 0 as well.

Solving a Single Variable Equation :

2.2 Solve : x+5 = 0

Subtract 5 from both sides of the equation :

x = -5

Solving a Single Variable Equation :

2.3 Solve : -x+5 = 0

Subtract 5 from both sides of the equation :

-x = -5

Multiply both sides of the equation by (-1) : x = 5

Two solutions were found :

x = 5

x = -5

Processing ends successfully

plz mark me as brainliest :)

6 0

4 years ago