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mrs_skeptik [129]
3 years ago
13

Please help me i really need help please

Mathematics
1 answer:
maw [93]3 years ago
3 0

Answer:

39°

Step-by-step explanation:

IM assuming xyz is a triangle

180 - 113 - 28 = 67 - 28 = 39

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Help please quickly if possible
rusak2 [61]

Answer:

i dont get the question

Step-by-step explanation:

3 0
4 years ago
PLEASE HELP ME WITH THIS QUESTION PLEASE
Ugo [173]

Answer:

a. 2.2 m

b. 8 m

Step-by-step explanation:

4) a. Sin 32 = x/4

= (sin 32)(4) = x

b. Cos 65 = 4.5/x

x = 4.5/Cos 65

6 0
3 years ago
Given the coordinates of the vertices of a quadrilateral, determine whether it is a square, a rectangle, or a parallelogram. The
vodomira [7]

Answer:

2) ABCD is  a RECTANGLE.

Perimeter  =  30 units

Step-by-step explanation:

Here, the given points of the quadrilateral are:

A(6, –4), B(11, –4), C(11, 6), D(6, 6)

Now, if P(a,b) and Q(c,d) are any two given points, then the distance between them is given by DISTANCE FORMULA as:

PQ = \sqrt{(c-a)^2 + (d-b)^2

Use this to find the length of all 4 sides:

AB with coordinates A(6, –4), B(11, –4)  is given as:

AB = \sqrt{(11-6)^2 + (-4-(-4))^2} =  \sqrt{(5)^2 + 0} = 5

⇒ AB = 5 units

BC with coordinates B(11, –4), C(11, 6)  is given as:

BC = \sqrt{(11-11)^2 + (6-(-4))^2} =  \sqrt{(0)^2 + 10^2} = 10

⇒ BC = 10 units

CD with coordinates C(11, 6), D(6, 6)  is given as:

CD = \sqrt{(11-6)^2 + (6-6)^2} =  \sqrt{(5)^2 + 0} = 5

⇒ CD = 5 units

AD with coordinates A(6, –4),D(6, 6)  is given as:

AD = \sqrt{(6-6)^2 + (-4-(-4))^2} =  \sqrt{(0)^2 + 10^2} = 10

⇒ AD = 10 units

Now, here AB  = CD =  5 units, AD = BC  = 10 units

Also, in a RECTANGLE, OPPOSITE SIDES ARE EQUAL IN LENGTH.

Hence, ABCD is  a RECTANGLE.

Perimeter  = AB + BC+ CD  + AD = 5 + 10 + 5 + 10 = 30 units

8 0
3 years ago
What number is 25% of 400 please show work thank you
ANEK [815]

Answer:

100

Step-by-step explanation:

well, you can just use a calculator, or your mind if that's possible, to solve this.

at least, what i think you're asking.

400 × 0.25 = 100.

this one is extra easy because you should know that 25% is a quarter, and 400 can just be divided by 4 to get your answer.

6 0
2 years ago
The half-life of cesium-137 is 30 years. Suppose we have a 20 mg sample.
Tju [1.3M]

Answer:

(a) A = (20mg)/(2^(t/30))

(b) 12.6mg

(c) 129.6years

Step-by-step explanation:

To calculate the amount remaining after a number of half-lives, n, we can make use of:

A = \frac{B}{2^n}

Where A = amount remaining

B = initial amount

n = \frac{t}{t_{0.5}}

(a) A = (20mg)/(2^(t/30))

(b) Mass after 20years

A = (20mg)/(2^(20/30)) ≈ 12.6mg

(c) After how long will only 1mg remain:

1mg = (20mg)/(2^(t/30))

20mg = {2^{\frac{t}{30}}

Taking log of both sides we have:

Log(20) = (t/30)log(2)

t/30 = (log(20))/(log(2)) ≈ 4.3

t/30 = 4.3

t = 30 x 4.3 ≈ 129.6years.

8 0
3 years ago
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