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vovikov84 [41]
3 years ago
14

12) Findthe side lengths of cach triangle in the graph that relate to the slope of the line. ​

Mathematics
1 answer:
Alexxx [7]3 years ago
3 0

Step-by-step explanation:

for the triangle on the left side of the x-axis

the perimeter is :

{c}^{2}  =  {2}^{2}  +  {4}^{2}  \\  {c}^{2}  = 16 + 4 \\  {c}^{2}  = 20 \\ c =  \sqrt{20}  = 4.47

for the triangle on the right side of the x-axis

the perimeter is :

{c}^{2}  =  {3}^{2}  +  {6}^{2}  \\  {c }^{2}  = 9 + 36 = 45 \\c  =  \sqrt{45}  = 6.708 = 6.71

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Kipish [7]

297.3 to 295.?

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8 0
3 years ago
Which of the following is not the equation of the graphed line?
ehidna [41]

Answer:

well, we do not have the options here, but we can find the equation of the graph, so the equations that are different from that are the answer to this question:

in the graph, we can see that it goes through the points:

(0,1) and (2,0)

Remember that the slope of a line that goes through the points (x1, y1) and (x2, y2) is:

s = (y2 - y1)/(x2- x1)

then the slope for our line is:

s = (0 - 1)/(2 -0) = -1/2

Then our line is:

y = -(1/2)*x + b.

b is the y-intercept, and we know that when x = 0 y = 1, then:

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then the equation is:

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5 0
3 years ago
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nadezda [96]

Answer:

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Step-by-step explanation:

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6 0
3 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
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slavikrds [6]

Answer:

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Step-by-step explanation:

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8 0
4 years ago
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