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kakasveta [241]
2 years ago
10

PLEASEEE HELP WITH MARK BRAINLIEST!!! What is the value of k?

Mathematics
1 answer:
saveliy_v [14]2 years ago
5 0

Answer:

190 degrees or 1 degree

Step-by-step explanation:

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A model scale is 1cm=8m if the actual object is40 metersthe model is ​
solniwko [45]

Answer:

5cm

Step-by-step explanation:

40/8=5

1*5=5

6 0
3 years ago
20 POINTS
Brut [27]

Answer:

Substitute (x+4)2−16 ( x + 4 ) 2 - 16 for x2+8x x 2 + 8 x in the equation x2+y2+8x−6y=24 x 2 + y 2 + 8 x - 6 y = 24 . (x+4)2−16+y2−6y=24 ( x + 4 ) 2 - 16 + y 2 ...

Step-by-step explanation:

5 0
3 years ago
Round to the nearest hundredth. Express 160 pounds in kilograms
Marrrta [24]

Answer:

72.57 kg

Step-by-step explanation:

1 pound = .453592 kg

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3 years ago
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A 8-foot tall man is standing beside a 32-foot flagpole. The flagpole is
kipiarov [429]

Answer:

The flagpole's shadow is 16.875 feet longer than the man's shadow

Step-by-step explanation:

The total length of the shadow is expressed by taking its actual length by a factor that depends on the position of the sun which is constant for the man too. The expression is as follows;

Height of the shadow=actual height of the flagpole×factor

where;

length of the flagpole's shadow=22.5 feet

actual height of the flagpole=32 feet

factor=f

replacing;

22.5=32×f

32 f=22.5

f=22.5/32

f=0.703125

Using this factor in the expression below;

Length of man's shadow=actual height of man×factor

where;

length of man's shadow=m

actual height of man=8 feet

factor=0.703125

replacing;

length of man's shadow=8×0.703125=5.625 feet

Determine how much longer the flagpole's shadow is as follows;

flagpoles shadow-man's shadow=22.5-5.625=16.875 feet

The flagpole's shadow is 16.875 feet longer than the man's shadow

7 0
3 years ago
What is the solution to the expression -2-3-(-4)?
Setler [38]

Answer:

-1

Step-by-step explanation:

-2-3-(-4)=-2-3+4=-5+4=-1

7 0
3 years ago
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