Step-by-step explanation:
The bike cost $199 to get $199 you do a number line then label 520 then at the end label 321 so then you do -20 then -100 then -50 then -20 then -9. so now you add them up 20+100+50+20+9 which equals =199
so bike cost $199
then 520%×199= 1034.8
or 520%×321=1669.2
so the percentage is 1669.2 or 1034.8 probably 1669.2 but they bot count.
Answer:
17m³
Step-by-step explanation:
==>Given:
Prism with right triangular base with the following dimensions:
Height = 17m
Base area = area of the right triangle = ½×2×1 = 1m²
==>Required:
Volume of prism
==>Solution:
Volume of prism = Base area × height of prism
Volume of prism = 1m² × 17m
Volume = 17m³
Complete question :
Suppose that of the 300 seniors who graduated from Schwarzchild High School last spring, some have jobs, some are attending college, and some are doing both. The following Venn diagram shows the number of graduates in each category. What is the probability that a randomly selected graduate has a job if he or she is attending college? Give your answer as a decimal precise to two decimal places.
What is the probability that a randomly selected graduate attends college if he or she has a job? Give your answer as a decimal precise to two decimal places.
Answer:
0.56 ; 0.60
Step-by-step explanation:
From The attached Venn diagram :
C = attend college ; J = has a job
P(C) = (35+45)/300 = 80/300 = 8/30
P(J) = (30+45)/300 = 75/300 = 0.25
P(C n J) = 45 /300 = 0.15
1.)
P(J | C) = P(C n J) / P(C)
P(J | C) = 0.15 / (8/30)
P(J | C) = 0.5625 = 0.56
2.)
P(C | J) = P(C n J) / P(J)
P(C | J) = 0.15 / (0.25)
P(C | J) = 0.6 = 0.60
Answer:
- y= -12
- x = 7
- q = -1
- x = 24
Step-by-step explanation:
1. ..............................................
- 6(y + 7) = 2(y - 3)
- 6y + 42 = 2y - 6
- 6y - 2y = -6 - 42
- 4y = -48
- y = -12
2...............................................
- 3x + 2(x - 5) = 25
- 3x + 2x - 10 = 25
- 5x = 25 + 10
- 5x = 35
- x = 7
3 . ..............................................
- 10q + 3q + 5 = 2(q - 3)
- 13q + 5 = 2q - 6
- 13q - 2q = -6 - 5
- 11q = -11
- q = -1
4. ..............................................
- 1/3(x + 6) = 2/3(x - 9)
- 3*1/3(x+6) = 3*2/3(x - 9)
- x + 6 = 2(x - 9)
- x + 6 = 2x - 18
- 2x - x = 6 + 18
- x = 24
F twice the 1st number minus 3 times the second number is 26<span>, </span>find both<span> ... </span>Twice the first number<span> is eleven more than </span>the sum<span> of the other </span>two numbers<span>.</span>
