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aliya0001 [1]
3 years ago
9

Insert 4 geometric means between 6and 92​

Mathematics
1 answer:
Digiron [165]3 years ago
7 0

Answer:

6    23.2    40.4     57.6    74.8      92

Step-by-step explanation:

92-6 = 86

86/5 spaces = 17.2 each

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How many acute, obtuse, and right angles are in this figure?
marta [7]
Hello!

Acute angles are angles less than 90°

A right angle is a angle that is exactly 90°

A Obtuse angle is a angle that is more than 90°

Looking at the picture there are

acute angles - 2
obtuse angles - 2
right angles - 0

Hope this helps!
5 0
3 years ago
Read 2 more answers
The graphs show the amounts in two different bank accounts over several months.
Neko [114]

Answer:

where are the graphs?

Step-by-step explanation:

3 0
2 years ago
for every 30 minutes of TV air time there are 8 minutes of commercial. If 90 minutes of TV or are now how many how many minutes
Anna35 [415]

Let m = minutes of commercial


30/90 = 8/m


Solve for m.


90(8) = 30m


720 = 30m


720/30 = m


24 = m

7 0
3 years ago
Read 2 more answers
I need help finding y
denpristay [2]

Answer:

y = 9.8995

Step-by-step explanation:

This question requires the use of basic trigonometry.

In this problem, we know one of the sides and two of the angles.

Since one of the angles is 45 degrees and the sum of all internal angles of a triangle is 180 degrees, the other angle can only be 45 degrees, making this an isosceles triangle - that is, the length of the other leg, x, is also 7.

You could use the soh cah toa mnemonic to figure it out, but here just using the a^2 + b^2 = c^2 should be sufficient since we know both legs of the triangle.

7^2 + 7^2 = 98, and the square root of 98 gives you about 9.8995, which sounds about right for this situation.

Hope this helped!

4 0
3 years ago
A motorboat takes 5 hours to travel 100mi going upstream. The return trip takes 2 hours going downstream. What is the rate of th
Temka [501]
The boat went 5hours upstream, let's say it has a "still water" speed rate of "b", it went 100miles... however, going upstream is going against the current, let's say the current has a speed rate of "c"

so, when the boat was going up, it wasn't really going "b" fast, it was going " b - c " fast, because the current was eroding speed from it

now, when coming down, the return trip, well the length is the same, so the distance is also 100miles, it only took 2hrs though, because, the boat wasn't coming down  "b" fast, it was coming down " b + c " fast, because the current was adding speed to it, so it came down quicker

now, recall your d = rt, distance = rate * time

\bf \begin{array}{lccclll}
&distance&rate&time\\
&-----&-----&-----\\
upstream&100&b-c&5\\
downstream&100&b+c&2
\end{array}
\\\\\\
\begin{cases}
100=(b-c)5\\
\qquad \frac{100}{5}=b-c\\
\qquad 20=b-c\\
\qquad 20+c=\boxed{b}\\
100=(b+c)2\\
\qquad 50=b+c\\
\qquad 50=\boxed{20+c}+c
\end{cases}

solve for "c", to see what's the current's speed

what's "b"?  well 20+c = b
4 0
3 years ago
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