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Natasha_Volkova [10]
3 years ago
13

You need 1 1/4 cups of sugar to make 20 cookies.

Mathematics
1 answer:
kirza4 [7]3 years ago
4 0
5/4 cups - 20 cookies
x cups - 14 cookies

x=((5/4)×14)÷20=0.875=7/8
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Robert is purchasing some equipment for his baseball team. He wants to buy some baseballs, each priced at m dollars. He has alre
KiRa [710]

Answer:

Part A: (1/2)m

Part B: (1/3rd)b and 3mx

Step-by-step explanation:

Price of each baseball is=$m

Price of other equipment are=$b collectively

Total amount He spent on purchasing equipment is =(m+b)$

Part A:

in part A the amount on purchasing other equipment than baseball is getting doubled i.e. $2b <u> then value of m will be (1/2)half of the total amount spent on purchasing baseball i.e. (1/2)m</u>

Part B:

in part B the amount spent on purchasing baseball is getting tripled i.e. <u>3m</u>, then value of b(amount of purchasing other equipment) is<u> (1/3rd) of total</u> <u>amount spent on purchasing other equipment</u> and value of mx will be<u> 3mx</u>

4 0
3 years ago
Calculate the pH of a buffer solution made by mixing 300 mL of 0.2 M acetic acid, CH3COOH, and 200 mL of 0.3 M of its salt sodiu
Lesechka [4]

Answer:

Approximately 4.75.

Step-by-step explanation:

Remark: this approach make use of the fact that in the original solution, the concentration of  \rm CH_3COOH and \rm CH_3COO^{-} are equal.

{\rm CH_3COOH} \rightleftharpoons {\rm CH_3COO^{-}} + {\rm H^{+}}

Since \rm CH_3COONa is a salt soluble in water. Once in water, it would readily ionize to give \rm CH_3COO^{-} and \rm Na^{+} ions.

Assume that the \rm CH_3COOH and \rm CH_3COO^{-} ions in this solution did not disintegrate at all. The solution would contain:

0.3\; \rm L \times 0.2\; \rm mol \cdot L^{-1} = 0.06\; \rm mol of \rm CH_3COOH, and

0.06\; \rm mol of \rm CH_3COO^{-} from 0.2\; \rm L \times 0.3\; \rm mol \cdot L^{-1} = 0.06\; \rm mol of \rm CH_3COONa.

Accordingly, the concentration of \rm CH_3COOH and \rm CH_3COO^{-} would be:

\begin{aligned} & c({\rm CH_3COOH}) \\ &= \frac{n({\rm CH_3COOH})}{V} \\ &= \frac{0.06\; \rm mol}{0.5\; \rm L} = 0.12\; \rm mol \cdot L^{-1} \end{aligned}.

\begin{aligned} & c({\rm CH_3COO^{-}}) \\ &= \frac{n({\rm CH_3COO^{-}})}{V} \\ &= \frac{0.06\; \rm mol}{0.5\; \rm L} = 0.12\; \rm mol \cdot L^{-1} \end{aligned}.

In other words, in this buffer solution, the initial concentration of the weak acid \rm CH_3COOH is the same as that of its conjugate base, \rm CH_3COO^{-}.

Hence, once in equilibrium, the \rm pH of this buffer solution would be the same as the {\rm pK}_{a} of \rm CH_3COOH.

Calculate the {\rm pK}_{a} of \rm CH_3COOH from its {\rm K}_{a}:

\begin{aligned} & {\rm pH}(\text{solution}) \\ &= {\rm pK}_{a} \\ &= -\log_{10}({\rm K}_{a}) \\ &= -\log_{10} (1.76 \times 10^{-5}) \\ &\approx 4.75\end{aligned}.

7 0
3 years ago
A 3-column table has 1 row. The first column is labeled Age with entry 7 years. The second column is labeled Mean with entry 49
alexandr1967 [171]

Answer:

47-51

45-53

43-55

Step-by-step explanation:

6 0
3 years ago
Plssss help meeeee!!!!!!!!!!!!!!!!!!!
igomit [66]

Answer:

b = -30

Step-by-step explanation:

-b/5 - 27 = -21

~Add 27 to both sides

-1/5b = 6

~Multiply -5 to both sides

b = -30

Best of Luck!

8 0
3 years ago
I have 1 apple I need 6 more to get to 7 so I pick 3 up eat 2 which picking up 4 more , how many apples do I have?
natita [175]

Answer:

6

Step-by-step explanation:

1+3=4  4-2=2  2+4=6

7 0
3 years ago
Read 2 more answers
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