It will be 5 out of 9 times you will pull a red marble
The answers is a because the radius must be 5
The classifications of the functions are
- A vertical stretch --- p(x) = 4f(x)
- A vertical compression --- g(x) = 0.65f(x)
- A horizontal stretch --- k(x) = f(0.5x)
- A horizontal compression --- h(x) = f(14x)
<h3>How to classify each function accordingly?</h3>
The categories of the functions are given as
- A vertical stretch
- A vertical compression
- A horizontal stretch
- A horizontal compression
The general rules of the above definitions are:
- A vertical stretch --- g(x) = a f(x) if |a| > 1
- A vertical compression --- g(x) = a f(x) if 0 < |a| < 1
- A horizontal stretch --- g(x) = f(bx) if 0 < |b| < 1
- A horizontal compression --- g(x) = f(bx) if |b| > 1
Using the above rules and highlights, we have the classifications of the functions to be
- A vertical stretch --- p(x) = 4f(x)
- A vertical compression --- g(x) = 0.65f(x)
- A horizontal stretch --- k(x) = f(0.5x)
- A horizontal compression --- h(x) = f(14x)
Read more about transformation at
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Answer:
The measure of the sum of interior angles of a 11-gon is
.
Each interior angle is approximately
.
Step-by-step explanation:
A convex polygon has the measure of each interior angles to be less than
.
But,
sum of interior angles of polygon = (n - 2) x ![180^{o}](https://tex.z-dn.net/?f=180%5E%7Bo%7D)
where n is the number of sides of the polygon.
For a convex 11-gon, we have;
sum of angles of a 11-gon = (11 - 2) x ![180^{o}](https://tex.z-dn.net/?f=180%5E%7Bo%7D)
= 9 x ![180^{o}](https://tex.z-dn.net/?f=180%5E%7Bo%7D)
= ![1620^{o}](https://tex.z-dn.net/?f=1620%5E%7Bo%7D)
Sum of angles of a 11-gon = ![1620^{o}](https://tex.z-dn.net/?f=1620%5E%7Bo%7D)
To check: convex polygons' interior angles are less than
.
so that,
each interior angle of 11-gon = ![\frac{1620}{11}](https://tex.z-dn.net/?f=%5Cfrac%7B1620%7D%7B11%7D)
= ![147.273^{o}](https://tex.z-dn.net/?f=147.273%5E%7Bo%7D)