All categories

3 years ago

What is the image point of (2, -5) after a rotation of 90 degrees counterclockwise about the origin?

Mathematics

1 answer:

meriva3 years ago

5 0

Answer:

(5,-2)

Step-by-step explanation:

(x, y)=(y, -x)

(2,-5)=(5,-2)

90° clockwise=(5,-2)

Mark the brainiest if correct

You might be interested in

A farmer raises only ducks and pigs. There are 55 animals in all on his farm, and 146 legs.

nordsb [41]

Answer:

Number of ducks = 37

Number of pigs = 18

Step-by-step explanation:

Let,

x be the number of ducks

y be the number of pigs

According to given statement;

x+y=55 Eqn 1

2x+4y=146 Eqn 2 (As ducks will have 2 legs and pigs will have 4)

Multiplying Eqn 1 by 2

2(x+y=55)

2x+2y=110 Eqn 3

Subtracting Eqn 3 from Eqn 2

(2x+4y)-(2x+2y)=146-110

2x+4y-2x-2y=36

2y=36

Dividing both sides by 2

$\frac{2y}{2}=\frac{36}{2}\\y=18$

Putting y=18 in Eqn 1

x+18=55

x = 55-18

x = 37

Hence,

Number of ducks = 37

Number of pigs = 18

8 0

3 years ago

When should you use dot plots and why?

MariettaO [177]

Dot plots are used for continuous, quantitative, univariate data. They can be also used for finding outliers, compare distributions, locate the central tendency of your data, etc…

3 0

2 years ago

A certain television is advertised as a 85 inch TV if the width of the TV is 67 how tall is the TV

Lunna [17]

Answer:

I believe the answer is 12

4 0

3 years ago

Read 2 more answers

In a survey 7/8 of the people surveyed said that recycling is important. Only 1/2 of them buy products made with recycled materi

morpeh [17]

Answer:

only 3.5 buy products made with recycled material but you have to round it to 4

5 0

3 years ago

If the endpoints of the diameter of a circle are (−8, −6) and (−4, −14), what is the standard form equation of the circle? A) (x

Andrei [34K]

Answer:

$\large\boxed{A.\ (x+6)^2+(y+10)^2=20}$

Step-by-step explanation:

The standard form of an equation of a circle:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - center

r - radius

We have the endpoints of the diameter of a circle (-8, -6) and (-4, -14).

The midpoint of a diameter is a center of a circle.

The formula of a midpoint:

$\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)$

Substitute:

$x=\dfrac{-8+(-4)}{2}=\dfrac{-12}{2}=-6\\\\y=\dfrac{-6+(-14)}{2}=\dfrac{-20}{2}=-10$

We have h = -6 and k = -10.

The radius is the distance between a center and the point on a circumference of a circle.

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute (-6, -10) and (-8, -6):

$r=\sqrt{(-8-(-6))^2+(-6-(-10))^2}=\sqrt{(-2)^2+4^2}=\sqrt{4+16}=\sqrt{20}$

Finally we have

$(x-(-6))^2+(y-(-10))^2=(\sqrt{20})^2\\\\(x+6)^2+(y+10)^2=20$

5 0

3 years ago

Read 2 more answers