Answer:
Step-by-step explanation:
We want to solve the equation:
In the interval [0, 2π).
Notice that this is in quadratic form. Namely, by letting u = sin(θ), we acquire:
Factor:
By the Zero Product Property:
Solve for each case:
Back-substitute:
Use the Unit Circle. Hence, our three solutions in the interval [0, 2π) are:
Answer:
The number of palindromes is
when n is even and
when n is odd
Step-by-step explanation:
From the question we are told that
The length of the string is
Generally palindrome is evaluated by considering the first part of a string
When the the length of the string is an even number then
it means that the first part of the string is
Hence the number of bit strings of length n that are palindromes is evaluated as
But When the the length of the string is an odd number then
it means that the first part of the string is
Hence the number of bit strings of length n that are palindromes is evaluated as
Generally each bit could be either 0 or 1
Hence the number of palindromes is
when n is even and
when n is odd
Look at the table for the people that used Lithium.
There are 18 relapses, 6 No relapses with a total of 24 people.
The relative frequency for relapse, would be dividing the number of relapses by the total number of people.
This would be D. 18 / 24 = 75%
To solve this problem you must apply the following proccedure:
1. <span>You have a total of 21 coins, all nickels and dimes. Then:
x:nickels=5 cents
y: dimes=10 cents
x+y=21
2. You have that the total value is $1.70. Then:
5x+10y=170
3. The system of equation is:
x+y=21 (i)
5x+10y=170 (ii)
4. You have:
x+y=21
x=21-y
5(21-y)+10y=170
105-5y+10y=170
y=13 dimes
x+13=21
x=8 nickels</span>