1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mylen [45]
3 years ago
10

Pre cal help??????????

Mathematics
1 answer:
klasskru [66]3 years ago
3 0
I believe it's the last one, but it's a matrix not a vector as the question asks
You might be interested in
A student takes an exam containing 1414 multiple choice questions. The probability of choosing a correct answer by knowledgeable
Readme [11.4K]

Answer:

0.0082 = 0.82% probability that he will pass

Step-by-step explanation:

For each question, there are only two possible outcomes. Either the students guesses the correct answer, or he guesses the wrong answer. The probability of guessing the correct answer for a question is independent of other questions. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

n = 14, p = 0.3.

If the student makes knowledgeable guesses, what is the probability that he will pass?

He needs to guess at least 9 answers correctly. So

P(X \geq 9) = P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 9) = C_{14,9}.(0.3)^{9}.(0.7)^{5} = 0.0066

P(X = 10) = C_{14,10}.(0.3)^{10}.(0.7)^{4} = 0.0014

P(X = 11) = C_{14,11}.(0.3)^{11}.(0.7)^{3} = 0.0002

P(X = 12) = C_{14,12}.(0.3)^{12}.(0.7)^{2} = 0.000024

P(X = 13) = C_{14,13}.(0.3)^{13}.(0.7)^{1} = 0.000002

P(X = 14) = C_{14,14}.(0.3)^{14}.(0.7)^{0} \cong 0

P(X \geq 9) = P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) = 0.0066 + 0.0014 + 0.0002 + 0.000024 + 0.000002 = 0.0082

0.0082 = 0.82% probability that he will pass

6 0
3 years ago
The line passes through the points ( 7, -7) and ( 6, -5) a. y = -2x + 7 c. y = -2x - 7 b. y = 2x - 21 d. y = 2x - 7
ollegr [7]
Slope = (-5+7)/(6 - 7) = -2

y = mx + b
b = y - mx
b = -7 - (-2)(7)
b = -7 + 14
b = 7

equation
y = -2x + 7

answer
<span>a. y = -2x + 7</span>
5 0
3 years ago
How do you work out this problem?
drek231 [11]
What is your question?
8 0
3 years ago
Find the length of x. Assume the triangles are similar. <br><br> A. 25<br> B. 12<br> C. 20<br> D. 19
Nady [450]

Answer:

it should be 12

Step-by-step explanation:

I hope this help

6 0
2 years ago
Read 2 more answers
If π is rounded to a whole number, what is a reasonable estimate for the circumference of a circle with a diameter of 9 cm? 27 c
a_sh-v [17]
The estimate would be about 28 cm
4 0
3 years ago
Read 2 more answers
Other questions:
  • How many yards are in 7 miles? A. 12,320 B. 700 C. 252 D. 36,960
    6·2 answers
  • Consider the following equation:
    12·1 answer
  • Name the property that the following statement illustrates. 44 • pie =pie•44
    9·2 answers
  • What 2 numbers multiplied together equal 35 but when added egual negative 36
    5·1 answer
  • Rearrange the formula to make a the subject
    7·1 answer
  • Complete the square to determine the minimum or maximum value of the function defined by the expression. x2 − 12x − 2
    9·1 answer
  • Type the equations and values needed to compute the difference between the market value of the car and its maintenance and repai
    6·1 answer
  • Simplify
    12·1 answer
  • What is an explicit formula for the geometric sequence -64,16,-4,1,... where the first term should be f(1).
    11·1 answer
  • Which of the following statements is true?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!