Answer18:
The quadrilateral ABCD is not a parallelogram
Answer19:
The quadrilateral ABCD is a parallelogram
Step-by-step explanation:
For question 18:
Given that vertices of a quadrilateral are A(-4,-1), B(-4,6), C(2,6) and D(2,-4)
The slope of a line is given m=
Now,
The slope of a line AB:
m=
m=
m=
The slope is 90 degree
The slope of a line BC:
m=
m=
m=
The slope is zero degree
The slope of a line CD:
m=
m=
m=
The slope is 90 degree
The slope of a line DA:
m=
m=
m=
m=
The slope of the only line AB and CD are the same.
Thus, The quadrilateral ABCD is not a parallelogram
For question 19:
Given that vertices of a quadrilateral are A(-2,3), B(3,2), C(2,-1) and D(-3,0)
The slope of a line is given m=
Now,
The slope of a line AB:
m=
m=
m=
The slope of a line BC:
m=
m=
m=
m=3
The slope of a line CD:
m=
m=
m=
The slope of a line DA:
m=
m=
m=3
The slope of the line AB and CD are the same
The slope of the line BC and DA are the same
Thus, The quadrilateral ABCD is a parallelogram
Answer:
There is no fixed domain, meaning it is ongoing
The range is from -1 ≤ x ≤ 3
It is a function
Step-by-step explanation:
Domain refers to the x values. If there was a domain then there would be a dot or a point signalling that there is a fixed domain, however, there are arrows meaning that it will keep going.
The range refers to the y-values. The lowest y-value is -1 and the highest is 3.
It is a function because, when you do the vertical line test, each x-value has its own y-value.
Step-by-step explanation:
4^5 (-2)^9/4^8 (-2)^3
= 4^(5 - 8) (-2^(9 - 3))
= 4^-3 (-2^6)
= (-2)^6/4^3
1). (-2)^a/4^b
a = 6, b = 3
2). c/d
c = -2, d = 4
Answer:
inflation is cause of change of price
Step-by-step explanation:
25 degrees is the answer. CBE is supplementary to ABC. That means those two angles add up to 180 degrees.