Answer:
a) Statement is true
b) Statement incorrect. Company goal is to attend customer at 190 second at the most. So test should be one tail test (right)
c) We have to reject H₀, and differences between sample mean and the hypothesized population mean should not be attributed only to sampling error
Step-by-step explanation:
a) as the significance level is = 0,02 that means α = 0,02 (the chance of error type I ) and the β (chance of type error II is
1 - 0.02 = 0,98
b) The company establishe in 190 seconds time for customer at its ticket counter (if this time is smaller is excellent ) company is concerned about bigger time because that could be an issue for customers. Therefore the test should be a one test-tail to the right
c) test statistic
Hypothesis test should be:
null hypothesis H₀ = 190
alternative hypothesis H₀ > 190
t(s) = ( μ - μ₀ ) / s/√n ⇒ t(s) = ( 202 - 190 )/(28/√100 )
t(s) = 12*10/28
t(s) = 4.286
That value is far away of any of the values found for 99 degree of fredom and between α ( 0,025 and 0,01 ). We have to reject H₀, and differences between sample mean and the hypothesized population mean should not be attributed only to sampling error
If we look table t-student we will find that for 99 degree of freedom and α = 0.02.
Answer:
36.8 or 37 yards of fabric
Step-by-step explanation:
23 yards of fabric = five dresses
23 divided by five equals four point six
four point six multiplied by eight dress equals 36.8
23 yds of fabric = 5 dresses
23÷5=4.6
If you need to know how many yards of fabric, then you'd do:
4.6×8
4.6 is the amount of each yards 5 dresses are in and so if you times that by how many dresses you need now, you'll get:
36.8 yards of fabric
To round, it'd be 37 yards of fabric
Answer:
im too late
Step-by-step explanation:
Answer:
261 of the graduates are planning to go to college.
Step-by-step explanation:
This is a proportion question.
x 45
___ = ___
580 100
First do 45 x 580 = 26,100
Then divide by 100 to get 261.
Answer:
<em>m∠C = 30° </em>
Step-by-step explanation:
If ΔADB is an equilateral, then m∠A = m∠ADB = m∠DBA = 60°
If ΔDBC isosceles with DB ≅ BC, then m∠C = m∠BDC ;
m∠C + m∠BDC = m∠DBA = 60° ⇒ <em>m∠C = 30°</em>
