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kogti [31]
2 years ago
15

What is the equation for a line that passes through the points (-5,-4) and (10,14)?

Mathematics
1 answer:
Vinvika [58]2 years ago
6 0

Answer:

y=6/5x+2

Step-by-step explanation:

1.find the slope(m)

m=y2-y1/x2-x1

m=14-(-4)/10-(-5)

m=14+4/10+5

m=18/15

m=6/5

y-y1=m(x-x1)

y-(-4)=6/5(x-(-5))

y+4=6/5(x+5)

y+4=6/5x+30/5

y=6/5x+30/5-4

y=6/5x+10/5

y=6/5x+2

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Someone help me out my grade are bad
nataly862011 [7]

Answer:

0.4

Step-by-step explanation:

hope this helps :)

4 0
3 years ago
Determine whether -6 is a solution of the inequality.<br> x = 6<br> Yes<br> No
const2013 [10]

Answer:

no

Step-by-step explanation:

x must be 6

6 0
2 years ago
Consider the region, R, bounded above by f(x)=x2−6x+9 and g(x)=−3x+27 and bounded below by the x-axis over the interval [3,9]. F
Salsk061 [2.6K]

Answer:

22.5

Step-by-step explanation:

The region R contains every point of the plane with coordinate x between 3 and 9, and with coordinate y positive such that y < f(x) and y < g(x).

We can note that both f and g are positive on [3,9] because g is a decreasing linear function and g(9) = 0, thus g is positive in every other point of the interval, and f(x) = (x-3)^2 is always positive excpept when x = 3, where it reaches the value 0.

The interception of the graphs takes place for a value x such that f(x) = g(x).

We compute x^2-6x+9 = -3x + 27, thus x^2-6x+9-(-3x + 27) = x^2-3x -18 = 0.

The roots of that quadratic function are

r_1, r_2 = \frac{3 ^+_- \sqrt { 9 +72}}{2} = \frac{3^+_-9}{2} , thus r1 = 6, r2 = -3. We dont care about -3 because it is outside the interval, but we know that f and g graphs intersects on x = 6. Thus, we obtain, due to Bolzano Theorem:

  • On the interval [3,6), the function f in smaller because it takes the value 0 on x=3, while g is always positive.
  • On the interval (6,9]. the function g is smaller because it takes the value 0 on x=9, while f is always positive

Hence, the upper bound is f on the interval [3,6) and g on the interval (6,9]. While the lower bound is the 0 function.

We need to calculate the following integral, using Barrow's rule

\int\limits^6_3 {x^2-6x+9} \, dx + \int\limits^9_6 {-3x+27} \, dx = (\frac{x^3}{3} - 3x^2 + 9x) |^6_3 + (\frac{-3x^2}{2} + 27x)|^9_6 = \\  (18 - 9) + (121.5-108) = 22.5

As a result, the area of the region R is 22.5

6 0
3 years ago
Suppose you invest $8,600 into a savings account with a 7.25% annual interest rate
Leto [7]

Answer:

16,507.38

Step-by-step explanation:

The equation for this would be 8600(1 + 0725/52)^52*9

9 is the years, 52 is the compounded weekly, and 8600 is the initial amount.

Solving the equation, we get:

16,507.38

4 0
2 years ago
Can 26/2 be grouped as a whole number?​
sweet [91]

Answer:

Yes

Step-by-step explanation:

The answer would be 13 because 26 divided by 2 is 13.

8 0
3 years ago
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