let's firstly convert both fractions with the same denominator, by simply <u>multiplying each fraction by the other's denominator</u>, let's proceed.
![\bf -\cfrac{3}{4}\cdot \cfrac{3}{3}\implies \boxed{-\cfrac{9}{12}}~\hfill -\cfrac{1}{3}\cdot \cfrac{4}{4}\implies \boxed{-\cfrac{4}{12}} \\\\[-0.35em] ~\dotfill\\\\ \boxed{-\cfrac{9}{12}}~~,~~\stackrel{-\frac{2}{3}}{-\cfrac{8}{12}}~~,~~-\cfrac{7}{12}~~,~~\stackrel{-\frac{1}{2}}{-\cfrac{6}{12}}~~,~~-\cfrac{5}{12}~~,~~\boxed{-\cfrac{4}{12}}](https://tex.z-dn.net/?f=%5Cbf%20-%5Ccfrac%7B3%7D%7B4%7D%5Ccdot%20%5Ccfrac%7B3%7D%7B3%7D%5Cimplies%20%5Cboxed%7B-%5Ccfrac%7B9%7D%7B12%7D%7D~%5Chfill%20-%5Ccfrac%7B1%7D%7B3%7D%5Ccdot%20%5Ccfrac%7B4%7D%7B4%7D%5Cimplies%20%5Cboxed%7B-%5Ccfrac%7B4%7D%7B12%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cboxed%7B-%5Ccfrac%7B9%7D%7B12%7D%7D~~%2C~~%5Cstackrel%7B-%5Cfrac%7B2%7D%7B3%7D%7D%7B-%5Ccfrac%7B8%7D%7B12%7D%7D~~%2C~~-%5Ccfrac%7B7%7D%7B12%7D~~%2C~~%5Cstackrel%7B-%5Cfrac%7B1%7D%7B2%7D%7D%7B-%5Ccfrac%7B6%7D%7B12%7D%7D~~%2C~~-%5Ccfrac%7B5%7D%7B12%7D~~%2C~~%5Cboxed%7B-%5Ccfrac%7B4%7D%7B12%7D%7D)
Distribute the 5 to the (2+y). Parenthisis always come first. after that combine the 5y and the -y. you should end up with 2-(+4y) +2. add the -2 and +2. you should be left with 4y
280 eels
92 + 56 + 52 = 200
eel = 56/200
56 *5 x
----- = --------
200 *5 1000
56(5) = 280 x = 280
56/200 = 7/25
7/25 = 280/1000
The missing figure is attached
The value of a is
⇒ 2nd answer
Step-by-step explanation:
Let as revise the Pythagoras Theorem
In the right triangle ABC, where ∠B is a right angle (AC is the hypotenuse, Ab and BC are the legs of the right angle)
- (AC)² = (AB)² + (BC)²
- (AB)² = (AC)² - (BC)²
- (BC)² = (AC)² - (AB)²
If BD is drawn perpendicular to AC, we can use these rules
- (AB)² = AD × AC
- (BC)² = CD × AC
- (BD)² = AD × CD
- AB × BC = BD × AC
In Δ WYZ
∵ m∠WYZ = 90°
- By using Pythagoras Theorem
∴ (WZ)² = (WY)² + (YZ)²
∵ WY = 4 units
∵ YZ = 3 units
∵ WZ = c units
∴ c² = (4)² + (3)²
∴ c² = 16 + 9 = 25
- Take √ for both sides
∴ c = 5
In Δ XWZ
∵ m∠XWZ = 90°
∵ WY ⊥ XZ
- We can use the rule (WZ)² = ZY × ZX
∵ (WZ)² = ZY × ZX
∵ WZ = 5 units
∵ ZY = 3 units
∵ ZX = (3 + a) units
∴ (5)² = 3(3 + a)
∴ 25 = 9 + 3a
- Subtract 9 from both sides
∴ 16 = 3a
- Divide both sides by 3
∴ a = 
The value of a is 
Learn more:
You can learn more about the rules of the right triangle in brainly.com/question/14390928
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