Answer:
1
Step-by-step explanation:
At point of intersection the two equations are equal,
hence, 6x³ =6x²
6x³-6x²=0
6x²(x-1)=0 , the values of x are 0 and 1
The points of intersection are therefore, (0,0) and (1,6)
To find the slopes of the tangents at the points of intersection we find dy/dx
for curve 1, dy/dx=12x, and the other curve dy/dx=18x²
At x=0, dy/dx=12x =0, dy/dx=18x² = 0, hence the angle between the tangents is 0, because the tangents to the two curves have the same slope which is 0 and pass the same point (0,0) origin.
At x=1, dy/dx =12x = 12, dy/dx= 18x² =18, Hence the angle between the two tangents will be given by arctan 18 -arctan 12
= 86.8202 - 85.2364 ≈ 1.5838, because the slope of the lines is equal to tan α where α is the angle of inclination of the line.
It will be 2/42 you count out the letters in “ALGEBRA” and then you can the A’s which equal a fraction 2/7 then you subtract 1 from the numerator and the denominator which then equals 1/6. Then you multiply the fractions and get 2/42
Well, the way I would do this is count the course and write that first, than put the 2 colins and than the carton of milk ratio. I hope this helped!
Answer:
x = 20
ABC = 85
BCA = 81
CAB = 14
Step-by-step explanation:
I answered your other question, so basically just read the explanation there cuz I'm too lazy to write it again :P
