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olya-2409 [2.1K]
3 years ago
5

Rewrite the function f(x)=2(x-2)^2-5 and in the form ax^2+bx+c

Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
7 0

Answer:

Step-by-step explanation:

f(x)=2(x-2)²-5

f(x)=2(x²-4x+4)-5

f(x)=2x²-8x+3

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Subtract the flat rate of 1.75 from the spending limit of 10$ which leaves you with 8.25 then divide the rest of your spending money (8.25$) into your rate per mile (0.65) , so essentially , 8.25 / 0.65 which leaves you with the answer of ;

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Step-by-step explanation:

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Write 33/72 in simplest form<br> 11/72<br> 33/24<br> 33/72<br> 11/24<br> please explain ...?
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A consumer group is interested in estimating the proportion of packages of ground beef sold at a particular store that have an a
snow_tiger [21]

Answer:

n=\frac{0.5(1-0.5)}{(\frac{0.05}{1.96})^2}=384.16  

And rounded up we have that n=385

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.05 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

We assume that the estimated proportion for this case is \hat p =0.5 since we don't have prior information.

And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.05}{1.96})^2}=384.16  

And rounded up we have that n=385

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