What is the percentage for 64 of 300

Which problem can be solved by expression 3/8 divided 1/4?

NeTakaya

Answer:

3/8÷1/4=1 1/2

Step-by-step explanation:

I am not sure what you are asking here, So I am gonna explain how you divide this.

So using the KCF method (Keep Change Flip) You would KEEP the first fraction (3/8) and CHANGE the operation (from divide to multiply) then FLIP your second fraction (1/4 to 4/1)

After doing this, it should look like:

3 4

x

8 1

Now that we got that, you multiply from left to right. 3×4 is 12. 8×1=8.

That should leave you with 12/8. But this is an improper fraction. So you would divide top by bottom to get a mixed fraction.

It should look like this

01. 1 1/2

8 12

8

4

Step by step explanation:

8 only goes into 12 one time. So you would subtract 12 by 8, and get 4. From that you would get 1 4/8 but 1 4/8 can be simplified to 1 1/2.

So it is 1 1/2

4 0

3 years ago

Find the function y = f(t) passing through the point (0, 18) with the given first derivative.

monitta

Answer:

$\displaystyle y = \frac{t^2}{16} + 18$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Functions
Function Notation
Coordinates (x, y)

Calculus

Derivatives

Derivative Notation

Antiderivatives - Integrals

Integration Constant C

Integration Rule [Reverse Power Rule]: $\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Step-by-step explanation:

Step 1: Define

Identify

Point (0, 18)

$\displaystyle \frac{dy}{dt} = \frac{1}{8} t$

Step 2: Find General Solution

Use integration

[Derivative] Rewrite: $\displaystyle dy = \frac{1}{8} t\ dt$
[Equality Property] Integrate both sides: $\displaystyle \int dy = \int {\frac{1}{8} t} \, dt$
[Left Integral] Integrate [Integration Rule - Reverse Power Rule]: $\displaystyle y = \int {\frac{1}{8} t} \, dt$
[Right Integral] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle y = \frac{1}{8}\int {t} \, dt$
[Right Integral] Integrate [Integration Rule - Reverse Power Rule]: $\displaystyle y = \frac{1}{8}(\frac{t^2}{2}) + C$
Multiply: $\displaystyle y = \frac{t^2}{16} + C$