A) part of it is decreasing, part of it is increasing.
Going left-to-right, the downhill/negative slope is the decreasing portion (x<-1) and the uphill/positive slope is the increasing portion (x>-1).
B) The x-intercepts are the points where the graph intersects the x-axis: (2,0) and (-4,0).
C: The y-intercept is the point where the graph intersects the y-axis: (0,-2).
D: There is no absolute maximum. The graph keeps going up forever.
E: The absolute minimum <u>point</u> is at that bottom, at (-1, -3). The absolute minimum <u>value</u> is -3, since that's the lowest y-value used.
Answer:
y+11=-2/3(x-6)
Step-by-step explanation:
To find the parallel line, we would just plug in the numbers in the point-slope form from what we're given. We have y=-2/3x+12 and (6,-11).
Point-slope form:
y-y1=m(x-x1) → y+11=-2/3(x-6)
m represents the slope, which is -2/3 in this situation.
y1 represents the y coordinate, which is -11 in this situation. However, when we plug in negative numbers in a point-slope form, we would do the opposite of the negative number, which is to make it a positive in point-slope form.
x1 represents the x coordinate, which is 6 in this situation.
4x^5 + 3x + 1...the ^5 makes it a fifth degree....and the leading coefficient is 4
ANSWER
See attachment.
EXPLANATION
The given function is
![y = \sqrt[3]{x + 1} - 2](https://tex.z-dn.net/?f=y%20%3D%20%20%5Csqrt%5B3%5D%7Bx%20%2B%201%7D%20%20-%202)
The parent function is
![y = \sqrt[3]{x}](https://tex.z-dn.net/?f=y%20%3D%20%20%5Csqrt%5B3%5D%7Bx%7D%20)
When we shift the parent graph to the left one unit, and down 2 units, we obtain the graph of the given function.
The graph of this function is shown in the attachment.
3/9 will fit on one bus so it will take 3 buses to fit 9/9 of the students, which 9/9 is the whole group.
