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inn [45]
3 years ago
15

Can somebody help me please

Mathematics
2 answers:
g100num [7]3 years ago
8 0

9514 1404 393

Answer:

  (b)  Output 6, Input 8

Step-by-step explanation:

One of the things you can look at is the ratio of output to input. Here, it is constant, which makes things a lot easier

  output/input = 12/2 = 30/5 = 66/11 = 6

Then for input 1, output is 1×6 = 6.

For unknown input, we have ...

  input × 6 = 48

  input = 48/6 = 8

__

The two blanks are ...

 input: 8; output 6

grin007 [14]3 years ago
5 0

Step-by-step explanation:

First, find complete data.

That would be 2, 12 and 5, 30

Divide the output by the input to get the relationship/constant.

12/2 = 6     30/5 = 6

So...

1 x 6 = 6

and

48 / 6 = 8

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The price of a shoes as reduced from 60 to 45. by what percentage was the price of the shoes reduced?
sweet-ann [11.9K]
45 is 75% of 60 but if you’re looking for the difference subtract 75 from 100, so 25%
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3 years ago
Last year 80 students signed up for a summer trip to Washington, D.C. This summer 50 students have signed up to go. What is the
Fynjy0 [20]

Given:

Last year 80 students signed up for a summer trip to Washington, D.C.

This summer 50 students have signed up to go.

To find:

The percent decrease in the number of students.

Solution:

We have,

Students in last year = 80

Students in this year = 50

Now,

\text{Decrease}\%=\dfrac{\text{Students in last year - Students in this year }}{\text{Students in last year }}\times 100

\text{Decrease}\%=\dfrac{80-50}{80}\times 100

\text{Decrease}\%=\dfrac{30}{80}\times 100

\text{Decrease}\%=\dfrac{3}{8}\times 100

\text{Decrease}\%=37.5

Therefore, the correct option is B.

7 0
3 years ago
The table shows the outputs, y, for different inputs, x: Input (x) 6 12 15 25 Output (y) 14 15 15 16 Part A: Do the data in this
cluponka [151]

Answer:

Part A: No it is not a function

Part B: The equation

Part C: x = 3

Step-by-step explanation:

Part A - The table:

Input (x)    Output (y)

6                14

12               15

15               15

25              16

This is a function because it has no repeating inputs values which have alternate outputs. Each input is assigned exactly one output.

Part B - The relation y = 7x - 15 has the value y = 27 when x = 6. You can find it by substituting into the equation.

y = 7(6) -15

y = 42 - 15

y = 27

The value of the relation in the table when x = 6 is y = 14. The equation has the greater value.

Part C: To find when y = 6, set it equal to 6 and solve for x.

6 = 7x - 15

21 = 7x

3 = x

5 0
3 years ago
A particular brand of tires claims that its deluxe tire averages at least 50,000 miles before it needs to be replaced. From past
Vadim26 [7]

Answer:

We conclude that deluxe tire averages less than 50,000 miles before it needs to be replaced which means that the claim is not supported.

Step-by-step explanation:

We are given that a particular brand of tires claims that its deluxe tire averages at least 50,000 miles before it needs to be replaced. From past studies of this tire, the standard deviation is known to be 8000.

From the 28 tires surveyed, the mean lifespan was 46,500 miles with a standard deviation of 9800 miles.

<u><em>Let </em></u>\mu<u><em> = average miles for deluxe tires</em></u>

So, Null Hypothesis, H_0 : \mu \geq 50,000 miles   {means that deluxe tire averages at least 50,000 miles before it needs to be replaced}

Alternate Hypothesis, H_A : \mu < 50,000 miles    {means that deluxe tire averages less than 50,000 miles before it needs to be replaced}

The test statistics that will be used here is <u>One-sample z test statistics</u> as we know about population standard deviation;

                                  T.S.  = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean lifespan = 46,500 miles

            \sigma = population standard deviation = 8000 miles

            n = sample of tires = 28

So, <u><em>test statistics</em></u>  =  \frac{46,500-50,000}{\frac{8000}{\sqrt{28} } }

                               =  -2.315

The value of the test statistics is -2.315.

Now at 5% significance level, the z table gives critical value of -1.6449 for left-tailed test. Since our test statistics is less than the critical value of z as -2.315 < -1.6449, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that deluxe tire averages less than 50,000 miles before it needs to be replaced which means that the claim is not supported.

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jolli1 [7]

Answer:

What's the question?

Step-by-step explanation:

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