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erica [24]
3 years ago
7

Manuel has $600 in a savings account at the beginning of the summer. He wants to have at least $300 in the account at the end of

the summer. He withdraws $28 each week for food. Which inequality represents w, the number of weeks Manuel can withdraw money while not dropping below a $300 balance?
28-600w < 300
28-600w > 300
600-28w < 300
600-28w > 300
Mathematics
1 answer:
baherus [9]3 years ago
7 0

Answer:

600-28·W>300

Step-by-step explanation:

This is because You start with $600 and then you loose $28 per week(W) so ir order to have more money than $300 it should be higher than $300 so=

600-28·W>300

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Aryan wants to plant a flower on the ground in the form of a rhombus. The diagonals of the rhombus measures 42 cm and 56 cm. Fin
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<u>Given</u><u> info</u><u>:</u><u>-</u>

Aryan wants to plant a flower on the ground in the form of a rhombus.The diagonals of the rhombus measures 42 cm and 56 cm.

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<u>Explanation</u><u>:</u><u>-</u>

Given that

rhombus.The diagonals of the rhombus measures 42 cm and 56 cm.

Let consider a rhombus ABCD

Let AC = (d1) = 42 cm

Let BD = (d2) = 56 cm

We know that

The digonals of a rhombus bisects each other at 90°.

AC = AO+OC

⇛ AC = 2 AO = 2 OC

⇛ AO = OC = AC/2

⇛ AO = OC = 42/2 = 21 cm

and

BD = BO+OD

⇛ BD = 2 BO = 2 OD

⇛ BO = OD = BD/2

⇛ BO = OD = 56/2 = 28 cm

We have,

∆AOB is a right angled triangle

By Pythagoras theorem,

AB² = AO²+OB²

⇛ AB² = 21²+28²

⇛ AB² = 441+784

⇛ AB² = 1225

⇛ AB = ±√1225

⇛ AB = ±35

AB is the length of the side which cannot be negative.

AB = 35 cm

We know that

All sides are equal in a rhombus

⇛ AB = BC = CD = DA

As we know

The Perimeter of a rhombus = 4×Side units

The perimeter of the rhombus ABCD

⇛ 4AB = 4BC = 4CD = 4DA

⇛ 4×35 cm

⇛ Perimeter = 140 cm

<em>∴</em><em> </em><em>T</em><em>he perimeter of the given field is 140 cm.</em>

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