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Slav-nsk [51]
3 years ago
8

Please help with my homework

Mathematics
2 answers:
nlexa [21]3 years ago
8 0

The user @Hrishii is correct about the value of angle B.

Once you know all three angles, you can use the law of sines to find the missing sides.

----------------------------------------------

Let's use the law of sines to find side b

b/sin(B) = a/sin(A)

b/sin(22) = 1/sin(18)

b = sin(22)*1/sin(18)

b = 1.21225240111352

b = 1.21  rounding to two decimal places

----------------------------------------------

Repeat for side c

c/sin(C) = a/sin(A)

c/sin(140) = 1/sin(18)

c = sin(140)*1/sin(18)

c = 2.08010440004024

c = 2.08  rounding to two decimal places

==============================================

The fully solved triangle is

A = 18 degrees

<h3>B = 22 degrees</h3>

C = 140 degrees

a = 1

<h3>b = 1.21</h3><h3>c = 2.08</h3>

decimal values are approximate

Lina20 [59]3 years ago
3 0

Step-by-step explanation:

\angle \: A  +  \angle \: B  +   \angle \:  C  = 180 \degree \\  \therefore \:  18 \degree  +  \angle \: B  +  140 \degree = 180 \degree  \\ \therefore \:  \angle \: B  +  158 \degree = 180 \degree  \\ \therefore \:  \angle \: B  = 180 \degree  - 158 \degree  \\   \huge \red{ \boxed{\therefore \:  \angle \: B  = 22 \degree}}

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