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Musya8 [376]
3 years ago
13

Solve for m.

Mathematics
1 answer:
Salsk061 [2.6K]3 years ago
7 0

Answer:

a

Step-by-step explanation:

solve for m. ;)

You might be interested in
The parabola is swached vertically by a factor of 5.
kobusy [5.1K]

Answer:

answer below

Step-by-step explanation:

I think you mean "squashed" or "stretched" vertically by a factor of 5.

f(x) is the original parabola equation

g(x) = 5f(x) is vertically stretched by a factor of 5

(x,y) -> (x , 5y)

5 0
3 years ago
How would u do this and can u explain
Amanda [17]


M=2-(-6)/(-1)-(-2)=8
Y=8x+b
-6=8*(-2)+b
-6=-16+b
B=16-6=10
Y=8x+10

I hope my answer is help to you
4 0
3 years ago
Determine if the system of equations has one solution, no solution or infinitely many solutions.
Paraphin [41]

Answer:

x

=

0

y

=

−

2

Explanation:

simply subtract each term in the second equation from the first equation:

3

x

+

4

y

=

−

8

3

x

+

16

y

=

−

32

(

3

x

−

3

x

)

+

(

4

y

−

16

y

)

=

(

−

8

−

(

−

32

)

)

(

0

)

+

(

−

12

y

)

=

(

−

8

+

32

)

−

12

y

=

24

y

=

−

2

now use either original equation to solve for

x

:

3

x

+

4

y

=

−

8

3

x

+

4

(

−

2

)

=

−

8

3

x

−

8

=

−

8

3

x

=

0

x

=

0

6 0
3 years ago
- (09.02)
sergeinik [125]

Answer:

1/3

Step-by-step explanation:

The only way it could be less than 9 is if the second cube is either 1 or 2. The probability of either of those outcomes is 2/6, simplified to be 1/3

4 0
3 years ago
Use a half-angle identity to find the exact value of tan 22.5°.
dusya [7]

Answer:

\sqrt{2} -1

Step-by-step explanation:

22.5 degrees is half of 45 degrees (special angle for which we know exactly the value of all three basic trigonometric functions (sine, cosine, and tangent).

So we start recalling the formula for tangent of a half angle: tan(\frac{\alpha }{2} )= \frac{1-cos(\alpha) }{sin(\alpha) }

We need just the values of:

sin(\alpha )=sin(45^o)=\frac{\sqrt{2} }{2}

and of

cos(\alpha )=cos(45^o)=\frac{\sqrt{2} }{2}

to answer the question. Then, we use those values in the original formula for tangent of a half angle:

tan(\frac{\alpha }{2} )= \frac{1-cos(\alpha) }{sin(\alpha) }\\tan(22.5^o)=\frac{1-\frac{\sqrt{2} }{2} }{\frac{\sqrt{2} }{2}} =\frac{2-\sqrt{2} }{\sqrt{2} } =\frac{2\sqrt{2}-2 }{2} =\sqrt{2} -1

3 0
3 years ago
Read 2 more answers
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