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Lerok [7]
3 years ago
15

Simplify 6 - (-2) - 3(-5)

Mathematics
2 answers:
seraphim [82]3 years ago
8 0

So the first thing we need to do is multiply 3*-5, since order of operations dictates it (PEMDAS)

6-(-2)-(-15)

Now, whenever we see a minus negative number, we can think of it as adding a positive number

6+(+2)+(+15)

Now we just add them together

6+2+15 = 23

23 is the answer

siniylev [52]3 years ago
5 0

Explanation: This question's it's about the order of operations. It stands for p-parenthesis, e-exponents, m-multiply, d-divide, a-add, and s-subtract. It can also go left too right.

First, multiply from left too right.

3(-5)=-15

Then, rewrite the problem down.

6-(-2)-(-15)

Next, add/subtract from left too right.

6-(-2)-3(-5)

6+2-(-15)

6+2=8

8-(-15)

8+15

\boxed{=23}

Hope this helps!

Thank you!

Have a great day!

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Evaluate each using the values given.<br> 7) 3 - x + x + y; use x = 4, and y=-1
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4 0
3 years ago
Help Q-Q 7/10c =4 1/5
shepuryov [24]

\huge\mathfrak\green{answer}

= q -   \frac{q7}{10} c =  \frac{41}{5}

\red{multiply}

= q -  \frac{cq7}{10} =  \frac{41}{5}

\red{subtract \: q \: from \: both \: sides}

= q -  \frac{cq7}{10}  - q =  \frac{41}{5} - q

\red{now \: simplify}

=  -  \frac{cq7}{10}  =  \frac{41}{5}  - q

\red{multiply \: 10 \: both \: sides}

= 10( -  \frac{cq7}{10} ) = 10. \frac{41}{5}  - 10q

\red{simplify}

=  - cq7 = 82 - 10q

\red{now \: divide}

=  \frac{ - cq7}{ - q7}  -  \frac{82}{ - q7}  -  \frac{10q}{ - q7}

\red{simplify}

= c =   - \frac{82 - 10q}{q7} (q≠0)

Brainliest? :) (I'd really appreciate if you mark me as brainliest)

\huge\mathfrak\green{thank \: you}

5 0
3 years ago
Read 2 more answers
0.34 times 10 with an exponet 3
STALIN [3.7K]

Answer: 340

Step-by-step explanation:

Because if you multiply 0.34x 10 to the 3rd power you get 340

Hope This helped :))

7 0
3 years ago
Read 2 more answers
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