3 years ago

Find the missing leg

Mathematics

1 answer:

alexgriva [62]3 years ago

8 0

Omg the legs are gonee

fr where are the legs

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tigry1 [53]

Answer:

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The equation is missing in the question.

The equation is, $h=-8t^2+40t$ , where 'h' is the height and 't' is time measured in second.

Now we know to reach its maximum height, h in t seconds, the derivative of h with respect to time t is given by :

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Now the differentiating the equation with respect to time t, we get

$\frac{dh}{dt}=\frac{d}{dt}(-8t^2+40t)$

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For maximum height, $\frac{dh}{dt} =0$

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3 years ago

How can you prove these triangles are congruent

diamong [38]

Answer:

Step-by-step explanation:

Side AB= Side DE

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