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Tasya [4]
3 years ago
6

HELP ASAP!!!!!!!!!!!!

Mathematics
2 answers:
choli [55]3 years ago
5 0

Answer: 40 yd²

Step-by-step explanation:

Find the area of the square:

4 × 4 = 16 yd²

Find the area of the triangle:

(6 × 8)/2 = 24 yd²

Add them together.

16 + 24 = 40 yd²

timofeeve [1]3 years ago
3 0

Answer:40 yd ^2

Step-by-step explanation:

multiply the parts

BRAINLEST PLEASE PLEASE PLEASE

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HELPPPPPPPPPP!!!!!!!!!!!!!!!!!!!! will give you a brainliest
spayn [35]

Answer:

a) m∠3=113°

b) x=8 (but check below)

Step-by-step explanation:

a) we know m∠1=m∠5

6x-5=5x+7

x=12

we also know m∠1+m∠3=180°

plug x into the formula for m∠1

m∠1=67

m∠1+m∠3=180°

67+m∠3=180°

m∠3=113°

b) Again, we know since those lines are parallel that m∠4=m∠8

x²-4x=32

x²-4x-32=0

(x-8)(x+4)=0

x=8 or x=-4

i think (not 100% sure about this part lol) but x cannot be negative so it's 8

again i'm not sure but it is either 8 or 8,-4.

4 0
3 years ago
Simpliftly(-8.5)(-5)( -2)<br><br>how do i simplify it​
Darina [25.2K]

Answer:

-85

Step-by-step explanation:

(-8.5)(-5)(-2)

Multiply

(42.5)(-2)

-85

Hope this helps :)

7 0
3 years ago
What is the circumference of the circle in terms of pi with a radius of 10in
o-na [289]

ANSWER

EXPLANATION

The circumference of a circle is calculated using the formula:

C=2\pi \: r

From the question, the radius of the circle is 10 inches.

We substitute the radius into the formula to get:

C=2\pi \times 10

Let us multiply out to get:

C=20 \pi \: in

The question required that we leave the answer in terms of π.

The correct choice is C.

7 0
3 years ago
Read 2 more answers
Which one has the same value as 1 hundred 7 tens
Valentin [98]
170? I think. I don't really understand your question
4 0
4 years ago
How would you use the Fundamental Theorem of Calculus to determine the value(s) of b if the area under the graph g(x)=4x between
-BARSIC- [3]
The Fundamental Theorem of Calculus regarding geometry states that 
\int\limits^b_a g{(x)} \, dx = F(b)-F(a)

Where F is the indefinite integral of g(x)

The first step is to integrate g(x)
\int\ {4x} \, dx = \frac{4x^{1+1} }{1+1} = \frac{4x^{2} }{2} =2 x^{2}

Then substitute the value of b and a=1 into 2x^{2}

[2 (b)^{2}]-[2 (1)^{2}] = 240
2b^{2} -2=240
2b^{2}=240+2
2b^{2}=242
b^{2}= \frac{242}{2}
b^{2}=121
b=11

Hence the limit of the area under g(x) is between a=1 and b=11

6 0
3 years ago
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