Expand and simplify this can you help (2x²−3x+4) ( x²+5x−7)

1 answer:

3 0

$(2x^2-3x+4) ( x^2+5x-7)= \\ \\=2x^2*x^2+2x^2*5x-2x^2*7-3x*x^2-3x*5x+3x*7+4*x^2+4*5x-4*7=\\ \\=2x^4+10x^3-14x^2 -3 x^3-15x^2+21x +4 x^2+20x-28=\\ \\=2x^4+7x^3-25x^2 +41x -28$

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1. Suppose you have a variable X~N(8, 1.5). What is the probability that you have values between (6.5, 9.5)

Natalija [7]

Answer:

0.6826 = 68.26% probability that you have values in this interval.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

X~N(8, 1.5)

This means that $\mu = 8, \sigma = 1.5$