All categories

3 years ago

Need help, will give a lot of points to whomever answers quickly!

Mathematics

2 answers:

Arte-miy333 [17]3 years ago

6 0

Step-by-step explanation:

ASA Axiom.
SSS Axiom
ASA Axiom

raketka [301]3 years ago

4 0

Step-by-step explanation:

The first figure triangles are congruent by ASA axiom.

The second figure triangles are congruent by SSS axiom.

The third figure triangles are congruent by ASA axiom.

Hope it will help :)

You might be interested in

HELP ASAP George plans to cover his circular pool for the upcoming winter season. The pool has a diameter of 20 feet and extends

enyata [817]

The pool has a diameter 20 ft so: r = 10 ft.
The pool cover extents 12 inches beyond the edge of the pool.
12 inches = 1 foot
Therefore, the radius of the pool cover is : r = 10 + 1 = 11 ft.
a. The area of the pool cover:
A = r² π = 11² π = 121 π ft²
b. The length of the rope:
l = 2 r π = 2 · 11 π = 22 π ft.

3 0

3 years ago

Can someone help me ASAP!!!

Dmitry_Shevchenko [17]

Answer:

3x+y=2

Step-by-step explanation:

Just remember that standard form is expressed as Ax+By=C. I also attached a picture to prove that 3x+y=2 is the standard form equation that makes up the line.

Hope this helps and answers your question :)

8 0

2 years ago

HELP ME QUICK: Suppose AB has one endpoint at A(0, 0). If (5, 3) is the midpoint of AB, what are the coordinates of point B?

DiKsa [7]

Answer:

Step-by-step explanation:

If P is midpoint of AB and: $A(0,\,0)\,,\quad P(5,\,3)\,,\quad B(x_B,\,y_B)$

then:

$x_P-x_A=x_B - x_P\qquad\quad\ \wedge\qquad y_P-y_A=y_B - y_P\\\\ 5-0=x_B-5\qquad\quad\wedge\qquad 3-0=y_B -3\\\\ x_B=5+5\qquad\qquad\wedge\qquad\ \ y_B=3+3 \\\\ {}\quad x_B=10\qquad\qquad\wedge\qquad\qquad \ y_B=6$

5 0

2 years ago

A Norman window is a window with a semi-circle on top of regular rectangular window. (See the picture.) What should be the dimen

Vikki [24]

Answer:

bottom side (a) = 3.36 ft

lateral side (b) = 4.68 ft

Step-by-step explanation:

We have to maximize the area of the window, subject to a constraint in the perimeter of the window.

If we defined a as the bottom side, and b as the lateral side, we have the area defined as:

$A=A_r+A_c/2=a\cdot b+\dfrac{\pi r^2}{2}=ab+\dfrac{\pi}{2}\left (\dfrac{a}{2}\right)^2=ab+\dfrac{\pi a^2}{8}$

The restriction is that the perimeter have to be 12 ft at most:

$P=(a+2b)+\dfrac{\pi a}{2}=2b+a+(\dfrac{\pi}{2}) a=2b+(1+\dfrac{\pi}{2})a=12$

We can express b in function of a as:

$2b+(1+\dfrac{\pi}{2})a=12\\\\\\2b=12-(1+\dfrac{\pi}{2})a\\\\\\b=6-\left(\dfrac{1}{2}+\dfrac{\pi}{4}\right)a$

Then, the area become:

$A=ab+\dfrac{\pi a^2}{8}=a(6-\left(\dfrac{1}{2}+\dfrac{\pi}{4}\right)a)+\dfrac{\pi a^2}{8}\\\\\\A=6a-\left(\dfrac{1}{2}+\dfrac{\pi}{4}\right)a^2+\dfrac{\pi a^2}{8}\\\\\\A=6a-\left(\dfrac{1}{2}+\dfrac{\pi}{4}-\dfrac{\pi}{8}\right)a^2\\\\\\A=6a-\left(\dfrac{1}{2}+\dfrac{\pi}{8}\right)a^2$