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3 years ago

In the data table shown, if x = 20, then y=

Mathematics

2 answers:

miskamm [114]3 years ago

7 0

Answer:

give us the table please

Step-by-step explanation:

IRISSAK [1]3 years ago

5 0

Answer:

we need the table!

Step-by-step explanation:

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Suppose the following regression equation was generated from the sample data of 50 cities relating number of cigarette packs sol

frez [133]

Answer:

A) According to the regression equation, regardless of whether or not smoking is allowed in bars, the number of cigarette packs sold per 1000 people decreases by approximately 1424 for each additional dollar of cigarette tax.

Step-by-step explanation:

Given the regression equation:

PACKS i= 57221.431732 − 1423.696906TAXi + 155.441784BARSi + eᵢ.

BARS i= 1 if city i allows smoking in bars

BARSi = 0 if city i does not allow smoking in bars

R2 = 0.351292

P-value = 0.086529

Conlusion:

Simnce p value, 0.0865 is greater than level of significance, 0.05, BARS is not significant. Thus, allowing smoking in bars increase cigarette sales, since the coefficient of BARS is positive.

Correct answer is option A.

According to the regression equation, regardless of whether or not smoking is allowed in bars, the number of cigarette packs sold per 1000 people decreases by approximately 1424 for each additional dollar of cigarette tax.

4 0

3 years ago

there are four semi trailer trucks parked in a line at the rest stop after the first truck each truck in the line weighs 2 tons

alexira [117]

Call the weght of the first truck " $w_{1}$ ". We then know that the truck after that is 2 tons more, and the next and the next. i.e:
$w_{2} = w_{1} + 2$
$w_{3} = (w_{2} + 2) = (w_{1}+4)$
$w_{4} = (w_{3} + 2) = (w_{1}+6)$

We also know that total is 32 tons.
$w_{total} = 32 = (w_{1}) + (w_{2}) + (w_{3}) + (w_{4})$
$32 = (w_{1})+(w_{1}+2)+(w_{1}+4)+(w_{1}+6)$
$32= 4(w_{1})+12$
$20=4(w_{1})$
$w_{1} = 5 tons$

Therefore the trukcs weigh 5,7,9 and 11 tons for a total of 32 tons.

Converting to pounds, the trucks weigh 10,000, 14,0000, 18,0000 and 22,000 pounds.

3 0

3 years ago

What is the answer to 9x8 2/3

Ira Lisetskai [31]

The answer is 78. This is because you change 8 2/3 into a improper fraction which is 26/3. Then do 26/3×9/1. You should cross cancel so cancel out 3 and change it into 1 and change 9 into 3. So now your problem is 26×3=78.
~JZ
Hope it helps.

7 0

3 years ago

Read 2 more answers

Use the Law of Sines to find the missing angle of the triangle. Find m<b to the nearest tenth.

defon

1. By the Law of Sines, you have:

SinA/a=SinB/b=SinC/c

2. You don't need the fraction SinC/c, so you can eliminate it. Then:

SinA/a=SinB/b

A=40°
a=19
B=m∠b
b=13

3. When you substitute this values into SinA/a=SinB/b, you obtain:

SinA/a=SinB/b
Sin(40°)/19=SinB/13
SinB=13xSin(40°)/19
m∠b=SinB^-1(13xSin(40°)/19)
m∠b=26.1°

Therefore, the answer is: 26.1 degrees.

6 0

2 years ago

One of the vertices of an equilateral triangle is on the vertex of a square and two other vertices are on the not adjacent sides

Elina [12.6K]

<h2>Answer:</h2>

<em> The side of the triangle is either 38.63ft or 10.35ft</em>

<h2>Step-by-step explanation:</h2>

This problem can be translated as an image as shown in the Figure below. We know that:

The side of the square is 10 ft.
One of the vertices of an equilateral triangle is on the vertex of a square.
Two other vertices are on the not adjacent sides of the same square.

Let's call:

Since the given triangle is equilateral, each side measures the same length. So:

x: The side of the equilateral triangle (Triangle 1)

y: A side of another triangle called Triangle 2.

That length is the hypotenuse of other triangle called Triangle 2. Therefore, by Pythagorean theorem:

$\mathbf{(1)} \ x^2=100+y^2$

We have another triangle, called Triangle 3, and given that the side of the square is 10ft, then it is true that:

$y+(10-y)=10$

Therefore, for Triangle 3, we have that by Pythagorean theorem:

$(10-y)^2+(10-y)^2=x^2 \\ \\ 2(10-y)^2=x^2 \\ \\ \\ \mathbf{(2)} \ x^2=2(10-y)^2$

Matching equations (1) and (2):

$2(10-y)^2=100+y^2 \\ \\ 2(100-20y+y^2)=100+y^2 \\ \\ 200-40y+2y^2=100+y^2 \\ \\ (2y^2-y^2)-40y+(200-100)=0 \\ \\ y^2-40y+100=0$

Using quadratic formula:

$y_{1,2}=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ y_{1,2}=\frac{-(-40) \pm \sqrt{(-40)^2-4(1)(100)}}{2(1)} \\ \\ \\ y_{1}=37.32 \\ \\ y_{2}=2.68$

Finding x from (1):

$x^2=100+y^2 \\ \\ x_{1}=\sqrt{100+37.32^2} \\ \\ x_{1}=38.63ft \\ \\ \\ x_{2}=\sqrt{100+2.68^2} \\ \\ x_{2}=10.35ft$

<em>Finally, the side of the triangle is either 38.63ft or 10.35ft</em>

5 0

3 years ago

Read 2 more answers