Question 1
1 answer:
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Answer:
Seven segments
Explanation:
As given in the question -
After every twenty microseconds one reaction occurs i.e breakdown of polysaccharides.
This means that after every twenty microseconds the polysaccharides is broken down
The total time for this hydrolysis reaction is micro seconds
Thus , there will be six phases of division each after every twenty microseconds
After 1st twenty microseconds , total segments is equal to two
After 2nd twenty microseconds , total segments is equal to three
After 3rd twenty microseconds , total segments is equal to four
After 4th twenty microseconds , total segments is equal to five
After 5th twenty microseconds , total segments is equal to six
After 6th twenty microseconds , total segments is equal to seven
Two traits that we are examining are the color (purple/white) and the smoothness.
In our sample, we have 135 individuals ( 75 +28+24+8= 135).
Since we know that expected ratio of a dihybrid cross, is <span>9:3:3:1 we can calculate what is the expected values of each phenotype is.
So, for the white wrinkled phenotype, we expect that there will be one-sixteenth of the whole sample ( there are 16 parts of the whole sample 9+3+3+1=16).
So, we multiply the whole sample- 135 with one-sixteenth (or </span>0.0625) and get 8,4375.
When you calculate the values for all phenotypes you get results shown in the attached excel table.
When you have your expected and experimental values you compare them with a chi-square test. (The test determines if the difference between the expected and experimental results is statistically significant).
In our sample, we have 135 individuals ( 75 +28+24+8= 135).
Since we know that expected ratio of a dihybrid cross, is <span>9:3:3:1 we can calculate what is the expected values of each phenotype is.
So, for the white wrinkled phenotype, we expect that there will be one-sixteenth of the whole sample ( there are 16 parts of the whole sample 9+3+3+1=16).
So, we multiply the whole sample- 135 with one-sixteenth (or </span>0.0625) and get 8,4375.
When you calculate the values for all phenotypes you get results shown in the attached excel table.
When you have your expected and experimental values you compare them with a chi-square test. (The test determines if the difference between the expected and experimental results is statistically significant).