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enot [183]
3 years ago
5

Help please And thank you

Mathematics
2 answers:
Solnce55 [7]3 years ago
5 0

Answer:

Step-by-step explanation:

kari74 [83]3 years ago
4 0

Answer:

cant see image

Step-by-step explanation:

.

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Save me the headache
maxonik [38]

(9\sin2x+9\cos2x)^2=81

Taking the square root of both sides gives two possible cases,

9\sin2x+9\cos2x=9\implies\sin2x+\cos2x=1

or

9\sin2x+9\cos2x=-9\implies\sin2x+\cos2x=-1

Recall that

\sin(\alpha\pm\beta)=\sin\alpha\cos\beta\pm\cos\alpha\sin\beta

If \alpha=2x and \beta=\dfrac\pi4, we have

\sin\left(2x+\dfrac\pi4\right)=\dfrac{\sin2x+\cos2x}{\sqrt2}

so in the equations above, we can write

\sin2x+\cos2x=\sqrt2\sin\left(2x+\dfrac\pi4\right)=\pm1

Then in the first case,

\sqrt2\sin\left(2x+\dfrac\pi4\right)=1\implies\sin\left(2x+\dfrac\pi4\right)=\dfrac1{\sqrt2}

\implies2x+\dfrac\pi4=\dfrac\pi4+2n\pi\text{ or }\dfrac{3\pi}4+2n\pi

(where n is any integer)

\implies2x=2n\pi\text{ or }\dfrac\pi2+2n\pi

\implies x=n\pi\text{ or }\dfrac\pi4+n\pi

and in the second,

\sqrt2\sin\left(2x+\dfrac\pi4\right)=-1\implies\sin\left(2x+\dfrac\pi4\right)=-\dfrac1{\sqrt2}

\implies2x+\dfrac\pi4=-\dfrac\pi4+2n\pi\text{ or }-\dfrac{3\pi}4+2n\pi

\implies2x=-\dfrac\pi2+2n\pi\text{ or }-\pi+2n\pi

\implies x=-\dfrac\pi4+n\pi\text{ or }-\dfrac\pi2+n\pi

Then the solutions that fall in the interval [0,2\pi) are

x=0,\dfrac\pi4,\dfrac\pi2,\dfrac{3\pi}4,\pi,\dfrac{5\pi}4,\dfrac{3\pi}2,\dfrac{7\pi}4

5 0
3 years ago
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telo118 [61]
38 - 171 divided by 19 times 2
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3 years ago
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PLEASE ANSWER PICTURE SHOWN
nexus9112 [7]
The answer is A. The rest of the answers are not necessarily correct with the operations.
3 0
3 years ago
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Use the Distributive Property on 45x-6
Alexandra [31]

Answer:

<h3>180</h3>

Step-by-step explanation:

<h3>45 × -6 = 45 × [10+(-6)]</h3><h3>45 × (10-6)</h3><h3>45 × 4</h3><h3>180</h3>
5 0
3 years ago
What are the values of a1 and r of the geometric series?
tester [92]

Answer:

r = 1/3

= 1

Step-by-step explanation:

1 + 1/3 + 1/9 + 1/27 + 1/ 81

In this series a is the first  term = 1

r is the common ratio = 2nd term/1st term = 3rd term/ 2nd term

r = 1/3 ÷ 1 = 1/9 ÷ 1/3

r = 1/3

I hope this was helpful, please mark as brainliest

4 0
3 years ago
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