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luda_lava [24]
3 years ago
14

Pl help me WILL GIVE BRAINLIEST

Mathematics
1 answer:
hjlf3 years ago
6 0

Answer:

up

Step-by-step explanation:

Since this is written as y = function of x, it will open up or down

y = 3x^2 -5x -10

The coefficient of x^2 is positive so it will open up

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A line crosses through the points (0,2) and (-10, -16) Which of the following is the slope of the line?
Elodia [21]

Answer:

  9/5

Step-by-step explanation:

The slope between the two points can be found by ...

  m = (y2 -y1)/(x2 -x1)

  m = (-16-2)/(-10-0) = -18/-10

  m = 9/5

The slope of the line is 9/5. Perhaps this is a match to choice A.

3 0
3 years ago
Please Helppppp☺️☺️☺️☺️☺️
pishuonlain [190]
Hi there!

Since one of the angles in this set of 2 lines is a right angle, we know that every other angle is a right angle because vertical angles are congruent and that because each line has a total of 180 degrees.

Thus, Angle NDA and RDY are both 90 degrees and add up to 180 degrees.

Since the two angles add up to 180, they are supplementary angles.

Also, we should notice that those two angles are across each other. Thus, they are also vertical angles.

Your answers are choices B and C.

Have an awesome day! :)
6 0
3 years ago
4 - 10q = -2q + 10 - 9 q
andrew-mc [135]

Answer:

q = 6

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

3 0
3 years ago
Read 2 more answers
A road has a 10% grade, meaning increasing 1 unit of rise to every 10 units of run.
fenix001 [56]

The grade is the ratio of rise to run, i.e. the slope aka the tangent.

\tan \theta = \dfrac{1}{10}

\theta = \arctan 0.1 \approx 5.711^\circ

Answer: (a) 6 degrees

For part b, the road is the hypotenuse c of a right triangle whose tangent of the small angle is 1/10.    The height h or rise is the side opposite the small angle.

\sin\theta = \dfrac h c

h = c \sin \theta

We could just take the sine of the angle we got but let's get it from the tangent exactly.

\cos^2 \theta + \sin ^2 \theta = 1

Dividing by squared cosine

1 + \tan ^2 \theta = 1/\cos^2 \theta = 1/(1- \sin^2 \theta)

(1- \sin^2 \theta) = 1/(1 + \tan^2 \theta)

\sin^2 \theta = 1 - 1/(1 + \tan^2 \theta)

\sin^2 \theta = 1 - 1/(1 + (1/10)^2) = 1-1/(101/100) = 1/101

h = c \sin \theta = 2 \sqrt{1/101} \approx 0.199

Answer: (b) Rise of 0.199 km

6 0
4 years ago
Find the midpoint of the line segment with the given endpoints (9, -8) (-10, -2)
True [87]

Answer:

mid point=(-1/2,-5)

Step-by-step explanation:

5 0
3 years ago
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