Answer:
7/100
Step-by-step explanation:
Find the GCD (or HCF) of numerator and denominator
GCD of 70 and 100 is 10
Divide both the numerator and denominator by the GCD
70 ÷ 10
100 ÷ 10
Reduced fraction:
7
10
Therefore, 70/100 simplified to lowest terms is 7/10.
Draw a diagram to illustrate the problem as shown below.
Calculate the volume of the empty cone.
V₁ = (1/3)π*(6 in)²*(10 in) = 120π in³
Calculate the volume of the sphere.
V₂ = (4/3)π*(1.5 in)³ = 4.5π in³
The volume that can be filled with flavored ice is
V = V₁ - V₂ = 115.5π in³ = 362.85 in³
Answer:
The volume is 115.5π in³ or 362.9 in³ (nearest tenth)
Answer:
180 cm
Step-by-step explanation:
2(3*10) = 60
3*12 = 24
1/2(12*8) * 2 = 96
formula for a triangle is 1/2 b h
To find the total area of this figure, it would be easiest to find the area of the left part (rectangle) and then find the area of the right part (triangle), and then add the two area values together.
First, we will find the area of the rectangle, using the formula A = lw, where l is the length of the rectangle and w is the width of the rectangle.
The length of the rectangle is 13 cm and the width is 9 cm. If we substitute in these values into our equation, we get:
A = (13cm)(9cm)
A= 117 cm^2
Next, let’s find the area of the triangle, using the formula A=(1/2)bh, where b is the base of the triangle and h is the height.
The base of the triangle is 11 cm and the height of the triangle is 5 cm (found by subtracting 13-8 as seen in the figure). If we substitute in these values and simplify, we get:
A=1/2(11cm)(5cm)
A=1/2(55cm^2)
A=27.5 cm^2.
When we add together the area of the rectangle with the area of the triangle, we will get the total area of the figure.
117 cm^2 + 27.5 cm^2 = 144.5 cm^2
Your answer is 144.5 cm^2 or the first option.
Hope this helps!
Let
The origin of coordinates the tree
r1 = vector position of the child 1.
r2 = vector position of the child 2
Child 1:
r1 = (12i + 12j)
Child 2:
r2 = (-18i + 11j)
The scalar product will be given by:
r1.r2 = ((12) * (- 18)) + ((12) * (11)) = - 84
The scalar product of their net displacements from the tree is -84m ^ 2
