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Jlenok [28]
3 years ago
14

Every day, Jason runs for 34 minutes and lifts weights for 49 minutes. How many minutes will Jason spend working out in 8 days?

Mathematics
2 answers:
aniked [119]3 years ago
8 0

Answer:

664 minutes

Step-by-step explanation:

34 + 49 = 83

83 minutes a day

83 x 8 = 664

timurjin [86]3 years ago
6 0

Answer:223

Step-by-step explanation:

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Jay is training for a 5 mile run. He runs 6.4 miles a day. If he does this for the next 15 days, how many miles will he have run
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Step-by-step explanation:

6.4 miles per day

x miles per 15 days

cross multiply and get the answer of 96

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A section of a railway has a slope of approximately 0.46. In this section, a vertical change of 1 unit corresponds to a horizont
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The slope is the vertical change per 1 unit of horizontal change so:
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3 years ago
The distribution of the number of people in line at a grocery store has a mean of 3 and a variance of 9. A sample of the numbers
Airida [17]

Answer:

a) P(\bar X >4)=P(Z>\frac{4-3}{\frac{3}{\sqrt{50}}}=2.357)

P(Z>2.357)=1-P(Z

b) P(\bar X \frac{2.5-3}{\frac{3}{\sqrt{50}}}=-1.179)

P(Z

c)  

P(2.5 < \bar X< 3.5) = P(\frac{2.5-3}{\frac{3}{\sqrt{50}}}

P(-1.179Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the number of people of a population, and for this case we know that:

Where \mu=3 and \sigma=\sqrt{9}=3

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we want to find this probability:

P(\bar X >4)= P(z> \frac{4-3}{\frac{3}{\sqrt{50}}})

And using a calculator, excel or the normal standard table we have that:

P(Z>2.357)=1-P(Z

Part b

P(\bar X  \frac{2.5-3}{\frac{3}{\sqrt{50}}})

And using a calculator, excel or the normal standard table we have that:

P(Z

Part c

For this case we want this probability:

P(2.5 < \bar X< 3.5) = P(\frac{2.5-3}{\frac{3}{\sqrt{50}}}

And using a calculator, excel or the normal standard table we have that:

P(-1.179

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3 years ago
Please help me !! pls pls pls
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Answer:

aas congruence postulate

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