Pseudocode:
import random
fetch user input on a lucky number
insert input into variable - "response"
new variable, random = randint
condition to check wheather random is our response
display results
Python Code:
import random
def main():
response = int(input("Guess my lucky number, its between 1 and 100: "))
lucky_number = random.randint(1,100)
if response == lucky_number:
print(f"Wow you're right, it is {lucky_number}")
else:
print("Sorry, Try Again")
main()
Reminder:
intended for python3 as i included the format f
also it could be done without the import, just manually insert a number
i'll leave the post mortum to you
Answer:
Newton's first law states that an object will stay at rest or be in motion, unless an unbalanced force acts on it.
Answer:
#include <stdio.h>
void spaces(int n) {
for(int i=0; i<n; i++) {
putchar(' ');
}
}
void numbersdown(int n) {
for(int i=n; i>1; i--) {
putchar('0'+i);
}
}
void numbersup(int n) {
for(int i=1; i<=n; i++) {
putchar('0'+i);
}
putchar('\n');
}
int main(void) {
int number;
printf("Please enter a digit: ");
scanf("%d", &number);
for(int i=number; i>0; i--)
{
spaces(number-i);
numbersdown(i);
numbersup(i);
}
}
Explanation:
I deliberately separated the solution into different functions for readability. If needed, the code could be made much more compact.
