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Lostsunrise [7]
3 years ago
5

What’s the answer for this

Computers and Technology
1 answer:
attashe74 [19]3 years ago
3 0
I believe the answer is B<span />
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Fill in the blank: when you execute code in the source editor, the code automatically also appears in the___ a. Files tab b. Plo
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When you execute the code in source editor, then the code automatically also appears in the <u>R console</u>. Hence, option 'C' is the right answer.

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5 0
1 year ago
Voip service is interrupted during a power failure true or false
zysi [14]
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5 0
4 years ago
2. Write a program that calls creates an ArrayList of integer and calls the method minToFront described below. Print out the lis
Novosadov [1.4K]

Answer:

import java.util.ArrayList;

public class MinToFront {

   public static void minToFront(ArrayList < Integer > list){

       int miniIndex = 0;

       for(int j=1; j<list.size(); j++){

          if(list.get(miniIndex) > list.get(j))

               miniIndex = j;

      }

      // moving min to front

       int min = list.get(miniIndex);

       list.remove(miniIndex);

       list.add(0, min);

  }

  public static void main(String[] args) {

       ArrayList<Integer> list = new ArrayList<>();

      list.add(4);   //value store in list

      list.add(7);   //value store in list

      list.add(9);  //value store in list

      list.add(2);  //value store in list

      list.add(7);  //value store in list

      list.add(7);  //value store in list

      list.add(5);  //value store in list

       

      list.add(3);  //value store in list

       

      list.add(5);  //value store in list

       

      list.add(1);  //value store in list

       

      list.add(7);  //value store in list

       

      list.add(8);  //value store in list

       

      list.add(6);  //value store in list

       

      list.add(7);  //value store in list

       

      System.out.println(list);

      minToFront(list);

      System.out.println(list);

  }

}

Output:

[1, 4, 7, 9, 2, 7, 7, 5, 3, 5, 7, 8, 6, 7]

Explanation:

Firstly,we define a method minToFront(), than set an integer variable "miniIndex" to 0, than set a for loop and apply the following condition and inside the loop we apply the if condition, set an integer variable "min" in which we store the value and than we set the following list [4, 7, 9, 2, 7, 7, 5, 3, 5, 1, 7, 8, 6, 7], after that print the list and than print an output.

3 0
4 years ago
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