During an activity analysis, a human resources manager determined that an employee spent 1.7

SAT

1 answer:

drek231 [11]3 years ago

4 0

Answer: 42.5 hours

Explanation:

Let the number of hours that the employee work be represented by x.

Since the employee spent 1.7 hours making work calls one week, which was 4% of the employee's total work hours for the week, this can be represented in an equation as:

4% × x = 1.7

4/100 × x = 1.7

0.04 × x = 1.7

0.04x = 1.7

x = 1.7 / 0.04

x = 42.5 hours

The employee worked for 42.5 hours

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<h3>What are the confidence level?</h3>

The confidence stage refers to the proportion of probability, or certainty, that the self-belief c language could include the real populace parameter whilst you draw a random pattern many times.

We have this given info:
n = 92 = pattern length xbar = 90.6 = pattern imply
sigma =8.! = populace popular deviation
C=99% self-assurance level
Because n > 30 and due to the fact we recognize sigma, this permits us to apply the Z distribution (aka popular ordinary distribution).
At 99% self-assurance, the z essential price is more or less z = 2.576 use a reference sheet, table, or calculator to decide this.
The decrease sure of the self assurance c programming language (L) is more or less L = xbar - z*sigma/sqrt(n) L = 90.6-2.576*8.9/sqrt(92) perp= 88.209757568781 perp= 88.2
The top sure (U) of this self assurance c programming language is more or less U = xbar + z*sigma/sqrt(n) L = 88.209757568781 L = 88.2.
The top sure (U) of this self assurance c programming language is more or less U=xbar+z^ * sigma/sqrt(n) U = 90.6 + 2.576*8.9/sqrt(92) U = 92.990242431219
U = 93.0.
Therefore, the self assurance c programming language withinside the format (L, U) is about (88.2, 93.zero).