Answer:
a) We need to find p(x<68.15)
Standardize x to z, we have, z = (68.15-μ)/σ
=(68.15-57)/8.1
=1.38
Reading from standard normal tables,
p(z<1.38) =0.9162.
b) We need to find p(x>54.4)
Standardize x to z, we have, z = (54.4-μ)/σ
=(54.4-57)/8.1
=-0.32
Reading from standard normal tables,
p(z>-0.32) = 0.6255
The standard error of the difference of sample means is 0.444
From the complete question, we have the following parameters
<u>Canadians</u>
- Sample size = 50
- Mean = 4.6
- Standard deviation = 2.9
<u>Americans</u>
- Sample size = 60
- Mean = 5.2
- Standard deviation = 1.3
The standard error of a sample is the quotient of the standard deviation and the square root of the sample size.
This is represented as:
The standard error of the Canadian sample is:
So, we have:
The standard error of the American sample is:
So, we have:
The standard error of the difference of sample means is then calculated as:
This gives
Take square roots
Hence, the standard error of the difference of sample means is 0.444
Read more about standard errors at:
brainly.com/question/6851971
Is this a true or false question of are you just giving a fact?
Answer: 548.96
Explanation: first find the circumference of the circle in the cone: 8*8*3.14 = 200.96
next find the triangle's area: 8 * 7/2 = 348
then add together 200.96+348= 548.96