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timurjin [86]
2 years ago
9

Which number(s) is a whole number, but not a natural number?

Mathematics
2 answers:
ruslelena [56]2 years ago
7 0

Answer:

0 is a whole number but not natural number.

Step-by-step explanation:

The whole numbers are the numbers 0, 1, 2, 3, 4, and so on (the natural numbers and zero). Negative numbers are not considered "whole numbers." All natural numbers are whole numbers, but not all whole numbers are natural numbers since zero is a whole number but not a natural number.

Anna [14]2 years ago
6 0

Answer:

number 0

Step-by-step explanation:

The number 0 is a whole number but not a natural number. But we can say that natural numbers contain all the whole numbers except the number 0.

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One half multiplied by four sevenths
bagirrra123 [75]

Answer:

2/7.

Step--step explanation:

1/2 * 4/7.

Multiply the numerators and the denominators:

= 1*4 / 2*7

= 4 / 14    Now  divide numerator and denominator by 2:

=  2/7.

7 0
2 years ago
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6(1—a) =3(a—b)+1 4(b—2) =3a Consider the system of equations above. If (a, b) is the solution to the system, then what is the
Jet001 [13]
6-6a=3a-3b+1,    9a-3b=5
<span>4b - 8 =3a,           3a-4b=-8
</span> 
9a-3b=5
(3a-4b=-8 )*(-3 )

 
9a    -3b=    5
-9a+12b=+24
adding both equations
9b=29, b=29/9

3a=4b-8=4*29/9 -8=(4*29-8*9)/9 = 44/9
a=44/27
a-b=44/27 - 29/9=44/27 - 29*3/27=-43/27
this is a correct answer, unfortunately they do not have this choice, probably they made mistake somewhere. I even check the solution of equations by substitution values of a and b into equations

5 0
3 years ago
PLEASE HELP ASAP WILL GIVE 30 POINTS
kykrilka [37]

Answer:

C. \displaystyle (−∞, 5) ∪ (5, ∞)

Step-by-step explanation:

This is obvious the correct answer, considering that the denominator can NEVER equal zero.

I am joyous to assist you anytime.

3 0
3 years ago
Question (in need of help)
mr Goodwill [35]
<h3><u>Required</u><u> Answer</u><u>:</u><u>-</u></h3>

This is an right angle ∆ and the side lengths containing a right angle are 9 and 11.

By Pythagoras theoram,

{p}^{2}  +  {b}^{2}  =  {h}^{2}

where p is the perpendicular, b is the base and h is the hypotenuse.

Plugging the values,

{9}^{2}  +  {11}^{2}  =  {h}^{2}

Then,

h =  \sqrt{ {9}^{2}  +  {11}^{2} }

h = 14.12(approx.)

<h3><u>Hence:</u><u>-</u></h3>

The x of the right angled ∆ = <u>1</u><u>4</u><u>.</u><u>1</u><u>2</u>

6 0
2 years ago
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galina1969 [7]
The answer is 6 see photo for steps

8 0
2 years ago
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