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3 years ago

Pls help with all of them

Mathematics

1 answer:

Irina-Kira [14]3 years ago

3 0

6h is the same thing as saying 6 times h. If we plug 6 in for h, we get 6x6=36. 6x6 does equal 36, so h = 6 is a solution to the problem.

If you plug in 60 for y, you get 60-45=15. 60-45 actually does equal 15, so both sides are equal and y=60 is a solution to the problem

If you plug in x=1/4, you get 1/4 + 1/2 = 3/4. 1/2 = 2/4, and 2/4 + 1/4 = 3/4 so x=1/4 is a solution to the problem

If you plug in w=2 for #5, you get 6x2=120. 6x2 equals 12, not 120, so w=2 is not a solution to the problem

If you plug in n=30 into #6, you get 30/3=12. 30/3 = 10, not 12, so n=30 is not a solution.

Hope this helps!

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There is a missing content in the question.

After the statements and before the the options given; there is an omitted content which says:

Referring to Table 16-5, in testing the coefficient of X in the regression equation (0.117) the results were a t-statistic of 9.08 and an associated p-value of 0.0000. Which of the following is the best interpretation of this result?

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C. The quarterly growth rate in the number of contracts is significantly different from 0% (? = 0.05).

Step-by-step explanation:

From the given question:

The resulting regression equation can be represented as:

$\hat Y = 3.37 + 0.117 X - 0.083 Q_1 + 1.28 Q_2 + 0.617Q_3$

where;

the estimated number of contracts in a quarter X is the coded quarterly value with X = 0

the first quarter of 2010 Q1 is a dummy variable equal to 1 in the first quarter of a year and 0 otherwise

Q2 is a dummy variable equal to 1 in the second quarter of a year and 0 otherwise

Q3 is a dummy variable equal to 1 in the third quarter of a year and 0 otherwise

Our null and alternative hypothesis can be stated as;

Null hypothesis :

$H_0 :$ The quarterly growth rate in the number of contracts is not significantly different from 0% (? = 0.05)

$H_a:$ The quarterly growth rate in the number of contracts is significantly different from 0% (? = 0.05)

The decision rule is to reject the null hypothesis if the p-value is less than 0.05.

From the missing omitted part we added above; we can see that the t-statistics value = 9.08 and the p-value = 0.000 .

Conclusion:

Thus; we reject the null hypothesis and accept the alternative hypothesis. i.e

The quarterly growth rate in the number of contracts is significantly different from 0% (? = 0.05)

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