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Alinara [238K]
3 years ago
13

Pls help with all of them

Mathematics
1 answer:
Irina-Kira [14]3 years ago
3 0
6h is the same thing as saying 6 times h. If we plug 6 in for h, we get 6x6=36. 6x6 does equal 36, so h = 6 is a solution to the problem.

If you plug in 60 for y, you get 60-45=15. 60-45 actually does equal 15, so both sides are equal and y=60 is a solution to the problem

If you plug in x=1/4, you get 1/4 + 1/2 = 3/4. 1/2 = 2/4, and 2/4 + 1/4 = 3/4 so x=1/4 is a solution to the problem

If you plug in w=2 for #5, you get 6x2=120. 6x2 equals 12, not 120, so w=2 is not a solution to the problem

If you plug in n=30 into #6, you get 30/3=12. 30/3 = 10, not 12, so n=30 is not a solution.

Hope this helps!
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Question: Researchers in Pakistan wanted to better understand the effects of anthracycline (a chemotherapeutic drug) on the hear
Sedbober [7]

Using the normal distribution, it is found that:

1. His z-score was of Z = -1.88.

2. There is a 0.0301 = 3.01% probability that a randomly selected person has a smaller E/A ratio than the patient in question 1.

3. Z-score of z = 1.85, there is a 0.0322 = 3.22% probability that a randomly selected patient has a higher E/A ratio.

4. Due to the higher absolute value of the z-score, the first patient had a more extraordinary result.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem:

  • The mean is of \mu = 1.35.
  • The standard deviation is of \sigma = 0.33.

Item 1:

Considering his ratio, we have that X = 0.73, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.73 - 1.35}{0.33}

Z = -1.88

His z-score was of Z = -1.88.

Item 2:

The probability is the <u>p-value of Z = -1.88</u>, hence, there is a 0.0301 = 3.01% probability that a randomly selected person has a smaller E/A ratio than the patient in question 1.

Item 3:

Score of X = 1.96, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{1.96 - 1.35}{0.33}

Z = 1.85

The probability is 1 subtracted by the p-value of Z = 1.85, hence, 1 - 0.9678 = 0.0322 = 3.22% probability that a randomly selected patient has a higher E/A ratio.

Item 4:

Due to the higher absolute value of the z-score, the first patient had a more extraordinary result.

More can be learned about the normal distribution at brainly.com/question/24663213

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Find the DISTANCE of line segment AB with point A​
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