X^2 + 8x + 16 =
(x + 4)(x + 4) or (x + 4)^2
Answer:
304
Step-by-step explanation:
find the area of each side, then add together
top and bottom are 10*8= 80 80*2= 160
front and back are 10*4=40 40*2=80
left and right sides are 8*4=32 32*2=64
160+80+64=304
Answer:
The correct option is B.
Step-by-step explanation:
It is given that triangle A"B"C" is the image of triangle ABC after transformation.
From the given figure it is noticed that the point C lies on positive y-axis and point C" lies on negative x-axis.
It means the figure is rotated either counterclockwise 90° or clockwise 270°. The rotation rule is
The corresponding sides of image A"B"C" are smaller than the preimage ABC.
Since k<0, therefore the transformation shows the reduction. The dilation rule is
Option B is correct.
So first, you have to get two of the same variables to cancel out. Let's do this for x. In order for the x's to cancel out, we could multiply the bottom problem by 2.
(2) 3x-6y=24
After multiplying all the numbers by 2, you get the equation 6x-12y=48
The set of equations is now
-6x+2y=12
6x-12y=48
Now you can add them. The x variables cancel out, so you are left with the y variable.
2y+-12y=-10y and 12+48=60
Then you would divide 60 by -10 to get y=-6.
You would plug the answer for y into one of the original equations, lets do the top one. -6x+2y=12 becomes -6x+2(-6)=12
You'd multiply the 2 and -6 to get -12 so the equation is
-6x-12=12
The negative 12 turn positive and you add to both sides to get the -6x alone.
-6x-12=12
+12=12
-6x=24
Then divide 24 by -6
X=4
(-4,-6) is your final answer.
