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2 years ago

1/2 (12+8) • 52 - 17=_

Mathematics

2 answers:

sergij07 [2.7K]2 years ago

8 0

Answer:

503

Step-by-step explanation:

1/2(20) × 52 - 17 = (10)(52) - 17 = 503

qwelly [4]2 years ago

5 0

The answer to your question is 503

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Ps help me with this its urgent❤

Llana [10]

Answer:

y^6/x^2

Step-by-step explanation:

(y^3/2x^-1/2)^4= y^(4*3/2)x^(-1/2*4)=y^6x^-2= y^6/x^2

6 0

2 years ago

A swimming pool is represented on a coordinate grid with the following vertices: Vertex A is at (−2,−3) . Vertex B is at (−2,

Semmy [17]

Answer:

26 yards.

Step-by-step explanation:

We can find the distance walked by Jared by finding the distances between each of the given vertex of swimming pool. We will use distance formula to find the distances between each vertex.

$\text{Distance}=\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

$\text{Distance between vertex A and vertex B}=\sqrt{(-2--2)^{2}+(-3-5)^{2}}$

$\text{Distance between vertex A and vertex B}=\sqrt{(-2+2)^{2}+(-8)^{2}}$

$\text{Distance between vertex A and vertex B}=\sqrt{(0)^{2}+(-8)^{2}}$

$\text{Distance between vertex A and vertex B}=\sqrt{64}=8$

Now let us find distance between vertex B and vertex C.

$\text{Distance between vertex B and vertex C}=\sqrt{(-2-3)^{2}+(5-5)^{2}}$

$\text{Distance between vertex B and vertex C}=\sqrt{(-5)^{2}+(0)^{2}}$

$\text{Distance between vertex B and vertex C}=\sqrt{25}=5$

Now let us find distance between vertex C and vertex D.

$\text{Distance between vertex C and vertex D}=\sqrt{(3-3)^{2}+(5--3)^{2}}$

$\text{Distance between vertex C and vertex D}=\sqrt{(0)^{2}+(5+3)^{2}}$

$\text{Distance between vertex C and vertex D}=\sqrt{64}=8$

Now let us find distance between vertex D and vertex A.

$\text{Distance between vertex D and vertex A}=\sqrt{(3--2)^{2}+(-3--3)^{2}}$

$\text{Distance between vertex D and vertex A}=\sqrt{(3+2)^{2}+(-3+3)^{2}}$

$\text{Distance between vertex D and vertex A}=\sqrt{(5)^{2}+(0)^{2}}$

$\text{Distance between vertex D and vertex A}=\sqrt{25}=5$

Now let us add all these distances to find the total distance walked by Jared.

$\text{Total distance walked by Jared}=8+5+8+5$

$\text{Total distance walked by Jared}=26$

Since we have been given that one unit on the grid equals 1 yard, therefore, Jared walked a distance equal to 26 yards.

3 0

2 years ago

Which is larger 1000 feet or 300 yards?

Alexus [3.1K]

1 yard = 3 feet

300 yards = (3 ft) x (300) = 900 feet

<em>1,000 feet</em> is larger than 900 feet. It's also longer and farther.

5 0

2 years ago

Which situation can be modeled by the equation 705 – m= 430?<br> help !!!!

777dan777 [17]

Real world example could be:
Consider x is time in minutes
Consider y is the amount of fish food required in grams

The equation could then represent how much food (in grams) that a fish needs to be fed x minutes after it was previously fed.

6 0

2 years ago

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Why are tenths, fifths, and fourths easy to convert to percent's?

meriva

Because they all go into 100 easily. for example 10*10=100 5*20=100

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2 years ago