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2 years ago

1/2 (12+8) • 52 - 17=_

Mathematics

2 answers:

sergij07 [2.7K]2 years ago

8 0

Answer:

503

Step-by-step explanation:

1/2(20) × 52 - 17 = (10)(52) - 17 = 503

qwelly [4]2 years ago

5 0

The answer to your question is 503

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D) y=0.75x+1

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2 years ago

Y+5=x+3 in standard form

podryga [215]

Answer: x-y=2

Step-by-step explanation:

y+5=x+3; move variable (x) to the left-hand side and change the sign.

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y+x=3-5; reorder the terms

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x-y=2 is your answer! hope this helps!

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Find the 12th term of the following geometric sequence.<br> 3, 12, 48, 192

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3 years ago

Solve step by step solution then only i can do it plxx

Anuta_ua [19.1K]

Answer:

<h3><u>Let's</u><u> </u><u>understand the concept</u><u>:</u><u>-</u></h3>

Here angle B is 90°

So $\triangle ABC$ and $\triangle ABD$ Are right angled triangle

So we use Pythagoras thereon for solution

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>

First in triangle ABC

perpendicular=p=8cm

Hypontenuse =h =10cm

We need to find base=b

According to Pythagoras thereon

${\boxed{\sf b^2=h^2-p^2}}$

Substitutethe values

$\longrightarrow$ $\sf b^2=10^2-p^2$

$\longrightarrow$ $\sf b={\sqrt {10^2-8^2}}$

$\longrightarrow$ $\sf b={\sqrt{100-64}}$

$\longrightarrow$ $\bf b={\sqrt {36}}$

$\longrightarrow$ $\sf b=6$

$\therefore$ $\overline{BC}=6cm$

BD=BC+CD

$\longrightarrow$ $BD=9+6$

$\longrightarrow$ $BD=15cm$

Now in $\triangle ABD$

Perpendicular=p=8cm

Base =b=15cm

We need to find Hypontenuse =AD(x)

According to Pythagoras thereon

${\boxed {\sf h^2=p^2+b^2}}$

Substitute the values

$\longrightarrow$ $\sf h^2=8^2+15^2$

$\longrightarrow$ $\sf h={\sqrt {8^2+15^2}}$

$\longrightarrow$ $\sf h={\sqrt {64+225}}$

$\longrightarrow$ $\sf h={\sqrt {289}}$

$\longrightarrow$ $\sf h=17cm$

$\therefore$ ${\underline{\boxed{\bf x=17cm}}}$

3 0

2 years ago

Please help. Thank you

MariettaO [177]

Answer:

$105

Step-by-step explanation:

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2 years ago

Read 2 more answers