Answer:
the plane's current height above the ocean is 3.42 miles
Step-by-step explanation:
Given that the diagonal distance between the plane and the aircraft carrier is 10 miles.
What we need to find is the vertical distance between the plane and the aircraft carrier which is the plane's current height above the ocean. This can be gotten using sine rule.
For sine rule, you need a side and its opposite angle. For this question the triangle formed is a right angle triangle with diagonal distance, vertical distance and horizontal distance.
let a = diagonal distance = 10 miles
let the opposite angle to the diagonal distance be A = 90° (right angle)
let the vertical distance = b
let the opposite angle to the vertical distance be B = 20°
Sine rule states that 
∴ 
⇒ b = 3.42 miles
Therefore the plane's current height above the ocean is 3.42 miles
Answer: The answer is x = 6 units.
Step-by-step explanation: Please refer to the attached diagram
The diagram in the question shows two triangles placed on each other and for convenience sake has been labelled ABDCE. Triangle ABC is a right angled triangle, and so is triangle ADE. From the marks on the lines, we can infer that line AD is equal in measurement to line DB. Also line AE is equal in measurement to line EC.
Therefore we can see the similarity in both triangles, if AD and AE equals DB and EC, then it follows that DE equals BC.
Hence if AD = DB and
AE = EC, and
DE = BC
Then, x - 3 = ½x
(½x can also be expressed as x/2)
x - 3 = x/2
By cross multiplication we now have
2(x - 3) = x
2x - 6 = x
By collecting like terms we now have
2x - x = 6
x = 6
C and D.............................
Answer:
x=8
Step-by-step explanation:
3(x-10)=-6
3x-30=-6
3x=24
x=8
Answer:
$126,000
Step-by-step explanation:
16% of 150,000 is 24,000
150,000-24,000=126,000
