The answer is (-21, 13) for The second endpoint.
Let's start by calling the known endpoint L and the unknown K. We'll call the midpoint M. In order to find this, we must first note that to find a midpoint we need to take the average of the endpoints. To do this we add them together and then divide by 2. So, using that, we can write a formula and solve for each part of the k coordinates. We'll start with just x values.
(Kx + Lx)/2 = Mx
(Kx + 1)/2 = -10
Kx + 1 = -20
Kx = -21
And now we do the same thing for y values
(Ky + Ly)/2 = My
(Ky + 7)/2 = 10
Ky + 7 = 20
Ky = 13
This gives us the final point of (-21, 13)
Add six to each side I think
Answer:
The answer is below
Step-by-step explanation:
Given that Triangle PTS has all sides with equal lengths, it is considered is an equilateral triangle.
Similarly, with < TPS and <TSP aare both equilateral triangle because they have equal length.
Therefore, ∆ PQS and ∆ SRP are congruent based on side-angle-side theorem.
Similarly, given the fact that their congruent sides of congruent triangles are congruent, both Segment PQ is congruent to segment SR.
Also, Segment PR is congruent to segment SQ as a result of congruent sides of the congruent triangles are congruent.
Lastly, the ∆ PQR and ∆ SRQ are congruent based on the side-side-side theorem.
Answer:15/8
Step-by-step explanation:
The length of AC is 12 cm. BE=6 which is half of the line times it by two you get 12 cm and since its a square its the same for AC