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Multiply both 3 and 7 by 2, this gives you equivalent fractions (there are more possible equivalent equations of course)
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Answer:</h2>
The values of x for which the given vectors are basis for R³ is:
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Step-by-step explanation:</h2>
We know that for a set of vectors are linearly independent if the matrix formed by these set of vectors is non-singular i.e. the determinant of the matrix formed by these vectors is non-zero.
We are given three vectors as:
(-1,0,-1), (2,1,2), (1,1, x)
The matrix formed by these vectors is:
![\left[\begin{array}{ccc}-1&2&1\\0&1&1\\-1&2&x\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-1%262%261%5C%5C0%261%261%5C%5C-1%262%26x%5Cend%7Barray%7D%5Cright%5D)
Now, the determinant of this matrix is:
Hence,
ceiling(700/40) = ceiling(17.5) = 18 . . . . ceiling(x) is the smallest integer ≥ x.
The smallest integer multiple of 40 that is larger than 700 is 18.
The number of packages of buns will be 18*5 = 90.
The number of packages of hotdogs will be 18*4 = 72.
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These numbers will ensure that you have 20 bun/hotdog combinations left over. If you want to minimize leftovers, you would use 88 packages of buns and 70 packages of hotdogs. That would give you 4 buns and no hotdogs left over.
This is rationalising the denominator of an imaginary fraction. We want to remove all i's from the denominator.
To do this, we multiply the fraction by 1. However 1 can be expressed in an infinite number of ways. For example, 1 = 2/2 = 3/3 = 4n^2 / 4n^2 (assuming n is not zero!). Let's express 1 as the complex conjugate of the denominator, divided by the complex conjugate of the denominator.
The complex conjugate of (3 - 2i) is (3 + 2i). Then do what I just said:
4/(3-2i) * (3+2i)/(3+2i) = 4(3+2i)/(3-2i)(3+2i) = (12+8i)/(9-4i^2) = (12+8i)/(9+4) = (12+8i)/13
This is the answer you are looking for. I hope this helps :)
