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3 years ago

What is the measurement of < SRT

Mathematics

1 answer:

Oksanka [162]3 years ago

4 0

Answer:

The sum of all the angles of any triangle is 180°

So, 180 - (53 + 48) = 180 - 101 = 79

<SRT = 79°

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Which property of equality was used to solve this equation?

HACTEHA [7]

Division property of equality. They are dividing -5 to both sides.

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3 years ago

Larry wants to enlarge a cube with edges of 3cm so that it's volume will be 8 times larger. How long must each edge of the enlar

Monica [59]

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3 years ago

What’s the answer??????#9

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Answer:

Step-by-step explanation:Quadratics

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2 years ago

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A circular pizza is being made that will fit in a box that is 14 inches by 16 inches. A 2-inch border is needed between the edge

aliina [53]

Now, as the pizza is circular, so it does not matter about the box shape. If the box shape increases or decreases, the pizza shape is the same.

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8 0

3 years ago

Find the derivative.

krek1111 [17]

Answer:

$\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}$

General Formulas and Concepts:

Algebra I

Terms/Coefficients

Expanding/Factoring

Calculus

Differentiation

Derivatives
Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Quotient Rule]: $\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle f(x) = \frac{\sqrt{x}}{e^x}$

Step 2: Differentiate

Derivative Rule [Quotient Rule]: $\displaystyle f'(x) = \frac{(\sqrt{x})'e^x - \sqrt{x}(e^x)'}{(e^x)^2}$
Basic Power Rule: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}(e^x)'}{(e^x)^2}$
Exponential Differentiation: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{(e^x)^2}$
Simplify: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{e^{2x}}$
Rewrite: $\displaystyle f'(x) = \bigg( \frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x \bigg) e^{-2x}$
Factor: $\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0

3 years ago