From the graph, when x = 1, y = 57,000.
Replace x with 1 in the equations and see if any of the Y 's equal 57,000 :
y = -2610.82(1) + 47860.82 = 45,250
y = 219(1)^2 - 6,506.78(1) + 59,385 = 219 - 6506.78 + 59385 = 53,097.22
y = 54041.5(0.9)^1 = 48,637.35
y = 10,504.6 (1.1)^1 = 11,555.06
The second equation is the closest. so try another x value to see if it is close to the Y value:
Let's try x = 14:
y = 219(14)^2 - 6506.78(14) + 59,385 = 42924 - 91094.92 + 59385 = 11,214.08
This is close to Y = 12,00 shown on the graph
SO the closest equitation is y = 219x^2 - 6506.78x + 59385
Answer:
x^2 - 81
Step-by-step explanation:
There is a formula called the difference of squares, which is
(a+b)(a-b) = a^2 - b^2
Answer:
l = 9p/4 , l = 9p/4
Step-by-step explanation:
Given:
Perimeter = 9p
Find:
Length and width
Computation:
Assume;
Length = l
Perimeter = 2(l+b)
9p/2 = l+w
w = 9p/2 - l
Area = lb
Area = l(9p/2 - l)
Using differentiation
l = 9p/4
w = 9p/2 - l
w = 9p/2 - 9p/4
w = 9p/4
Step-by-step explanation:
1 kilometer
thank you very much
Answer:
C.
Step-by-step explanation:
= ![\sqrt[3]{8}^{x}\\](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B8%7D%5E%7Bx%7D%5C%5C)
= Since ![\sqrt[3]{} = ^{1/3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%7D%20%3D%20%5E%7B1%2F3%7D)
= So, It becomes :
= 
