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Artist 52 [7]
2 years ago
14

En un triángulo rectángulo A es un ángulo agudo y Sen A = 4/5 ¿Cuál será el valor de Tan A?

Mathematics
1 answer:
Nonamiya [84]2 years ago
6 0

Answer:

\displaystyle \tan A=\frac{4}{3}

Step-by-step explanation:

<u>Funciones Trigonométricas</u>

La identidad principal en trigonometría es:

sen^2A+cos^2A=1

Si sabemos que A es un ángulo agudo (que mide menos de 90°), su seno y coseno son positivos.

Dado que Sen A = 4/5, calculamos el coseno:

cos^2A=1-sen^2A

Sustituyendo:

\displaystyle cos^2A=1-\left(\frac{4}{5}\right)^2

\displaystyle cos^2A=1-\frac{16}{25}

\displaystyle cos^2A=\frac{25-16}{25}

\displaystyle cos^2A=\frac{9}{25}

Tomando raíz cuadrada:

\displaystyle cos\ A=\sqrt{\frac{9}{25}}=\frac{3}{5}

La tangente se define como:

\displaystyle \tan A=\frac{sen\ A}{cos\ A}

Substituyendo:

\displaystyle \tan A=\frac{\frac{4}{5}}{\frac{3}{5}}

\displaystyle \tan A=\frac{4}{3}

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You are making a poster to support your friend for homecoming. Your original photo is 4 inches by 6 inches. You want the photo o
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Answer:

9.

Step-by-step explanation:

We have been given that dimensions of original photo are 4 inches by 6 inches. We want the photo on the poster to be of dimensions 3 feet by 4 1/2 feet.            

First of all we will convert dimensions of poster from feet to inches.

3\text{ feet}=3\times 12 \text{ inches}=36\text{ inches}

4\frac{1}{2}\text{ feet}=4.5\times 12 \text{ inches}=54\text{ inches}

Now let us compare sides of our original photo with corresponding sides of poster.

\frac{36}{4} =9          

Now let us compare the second pair of corresponding sides.

\frac{54}{6} =9

We have seen that sides of poster are 9 times the sides of our original photo, therefore, the scale factor of this dilation is 9.      

5 0
3 years ago
At the grocery store, Matthew notices that it costs $2.48 for 40 ounces of jelly. What is the unit price?
kari74 [83]

Answer:

0.06 cents per ounce

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
COMPUTE<br><br> 3 ( 2 1/2 - 1 ) + 3/10
Juli2301 [7.4K]

Answer:

<h3>\boxed{ \frac{24}{5} }</h3>

Step-by-step explanation:

\mathsf{3(2 \frac{1}{2}  - 1) +  \frac{3}{10} }

Convert mixed number to improper fraction

\mathrm{3( \frac{5}{2}  - 1) +  \frac{3}{10} }

Calculate the difference

⇒\mathrm{3( \frac{5 \times 1}{2 \times 1} -  \frac{1 \times 2}{1 \times 2}  }) +  \frac{3}{10}

⇒\mathrm{ 3 \times( \frac{5}{2}  -  \frac{2}{2}) } +  \frac{3}{10}

⇒\mathrm{3 \times ( \frac{5 - 2}{2} ) +  \frac{3}{10} }

⇒\mathrm{3 \times  \frac{3}{2}  +  \frac{3}{10} }

Calculate the product

⇒\mathrm{ \frac{3 \times 3}{1 \times 2}  +  \frac{3}{10} }

⇒\mathrm{ \frac{9}{2}  +  \frac{3}{10}}

Add the fractions

⇒\mathsf{ \frac{9  \times 5}{2 \times 5}  +  \frac{3 \times 1}{10 \times 1} }

⇒\mathrm{ \frac{45}{10}  +  \frac{3}{10} }

⇒\mathrm{ \frac{45 + 3}{10 } }

⇒\mathrm{ \frac{48}{10} }

Reduce the numerator and denominator by 2

⇒\mathrm{ \frac{24}{5} }

Further more explanation:

<u>Addition </u><u>and </u><u>Subtraction</u><u> </u><u>of </u><u>like </u><u>fractions</u>

While performing the addition and subtraction of like fractions, you just have to add or subtract the numerator respectively in which the denominator is retained same.

For example :

Add : \mathsf{ \frac{1}{5}  +  \frac{3}{5}  =  \frac{1 + 3}{5} } =  \frac{4}{5}

Subtract : \mathsf{ \frac{5}{7}  -  \frac{4}{7}  =  \frac{5 - 4}{7}  =  \frac{3}{7} }

So, sum of like fractions : \mathsf{ =  \frac{sum \: of \: their \: number}{common \: denominator} }

Difference of like fractions : \mathsf{ \frac{difference \: of \: their \: numerator}{common \: denominator} }

<u>Addition </u><u>and </u><u>subtraction</u><u> </u><u>of </u><u>unlike </u><u>fractions</u>

While performing the addition and subtraction of unlike fractions, you have to express the given fractions into equivalent fractions of common denominator and add or subtract as we do with like fractions. Thus, obtained fractions should be reduced into lowest terms if there are any common on numerator and denominator.

For example:

\mathsf{add \:  \frac{1}{2}  \: and \:  \frac{1}{3} }

L.C.M of 2 and 3 = 6

So, ⇒\mathsf{ \frac{1 \times 3}{2 \times 3}  +  \frac{1 \times 2}{3 \times 2} }

⇒\mathsf{ \frac{3}{6}  +  \frac{2}{6} }

⇒\frac{5}{6}

Multiplication of fractions

To multiply one fraction by another, multiply the numerators for the numerator and multiply the denominators for its denominator and reduce the fraction obtained after multiplication into lowest term.

When any number or fraction is divided by a fraction, we multiply the dividend by reciprocal of the divisor. Let's consider a multiplication of a whole number by a fraction:

\mathsf{4 \times  \frac{3}{2}  =  \frac{4 \times 3}{2}  =  \frac{12}{2}  = 6}

Multiplication for \mathsf{ \frac{6}{5}  \: and \:  \frac{25}{3} } is done by the similar process

\mathsf{ =  \frac{6}{5}  \times  \frac{25}{3}  = 2 \times 5 \times 10}

Hope I helped!

Best regards!

5 0
3 years ago
Ezra is training for a track race. He starts by sprinting 100 yards. He gradually increases his distance, adding 5 yards a day f
Sergeu [11.5K]
On the 21st day, he sprints 205 yards.

Is that what you meant for the problem

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I need this done by 11:59 tonight. If anyone can please help me with this problem!
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