Answer:
c
Step-by-step explanation:
hope it helps
Answer:
whts the question??
Step-by-step explanation:
The cost of children’s ticket is $ 5
<h3><u>Solution:</u></h3>
Let "c" be the cost of one children ticket
Let "a" be the cost of one adult ticket
Given that adult ticket to a museum costs 3$ more than a children’s ticket
<em>Cost of one adult ticket = 3 + cost of one children ticket</em>
a = 3 + c ------ eqn 1
<em><u>Given that 200 adult tickets and 100 children tickets are sold, the total revenue is $2100</u></em>
200 adult tickets x cost of one adult ticket + 100 children tickets x cost of one children ticket = 2100

200a + 100c = 2100 ------ eqn 2
<em><u>Let us solve eqn 1 and eqn 2 to find values of "a" and "c"</u></em>
Substitute eqn 1 in eqn 2
200(3 + c) + 100c = 2100
600 + 200c + 100c = 2100
600 + 300c = 2100
300c = 1500
<h3>c = 5</h3>
Thus the cost of children’s ticket is $ 5
If three hens lay 3 eggs any 3 days. The number of days that 3 Hens give in 9 eggs is: 9days.
<h3>
Number of days that three hens lay 9 eggs</h3>
Given:
3 hens lay 3 eggs in 3 days
First step is to determine the number of egg one hen lay in 3 days
1 hen in 3 days lays 3/3
1 hen in 3 days lays=1 egg
Second step is to determine the number of egg 3 hens lay 1 day
1 hen in 1 day lays 1/3 egg
3 hens in 1day lay=(1×3)/3
3 hens in 1day lay=1 egg
Third step is to determine the number of eggs 3 hens lay in 9 days
3 hens in 9 days lay=(1×9)
3 hens in 9 days lay=9 eggs
Therefore assuming three hens lay 3 eggs any 3 days. The number of days that 3 Hens give in 9 eggs is: 9days.
Learn more about number of days that three hens lay 9 eggs here: brainly.com/question/9286901
#SPJ1
Hi!
okay say you have the fractions 1/4 and 6/24, these two fractions are equivalent because you can multiply the numerator and the denominator by 6 to get 6/24 (1x6 = 6 and 4x6 = 24).
similarly you can reduce 6/24 to 1/4 by dividing the numerator and denominator by 6 (6/6 = 1 and 24/6 = 4).
i hope this helped!