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3 years ago

3. In the following formal proof, what is the missing reason?

Mathematics

2 answers:

Lana71 [14]3 years ago

6 0

Answer:

Step-by-step explanation:

Start with 2x = 12, and end with x = 6.

To do that, you need to divide both sides by 2.

Answer: A

AlladinOne [14]3 years ago

3 0

The answer is A
I just know it

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Suppose that Fx) = x3 and G(x) = -2x2. Which statement best compares the

Rudiy27

Answer:

Step-by-step explanation:

you can just find the value of y and try some number of x

i.e. if x = 0, both of them will be 0

x = 1

G(x) result is -2

F(x) result is 1

x= -1

G(x) result will be 2

F(x) result is -1

so from these we can prove that G(x) is bigger graph than F(x) but flip vertically by y axis

8 0

3 years ago

How to solve for axis of symmetry for y=(x+2)(x-4)

lianna [129]

Answer:

x = 1

Step-by-step explanation:

you can first find the two zeroes

that would be

x + 2 = 0

x - 4 = 0

x = {-2, 4}

then you average them

-2 + 4 = 2

2 / 2 = 1

the aos is 1

5 0

2 years ago

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Can someone pls help me with this?

Hatshy [7]

Answer:

Between 1 and 3 seconds

Step-by-step explanation:

There is no change in distance ( change in y ) between 1 and 3, so she wasn't walking during that time

4 0

2 years ago

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9/20

Stella [2.4K]

Question:

Find the number of real number solutions for the equation. x^2 + 5x + 7 = 0

Answer:

The number of real solutions for the equation $x^{2}+5 x+7=0$ is zero

Solution:

For a Quadratic Equation of form : $a x^{2}+b x+c=0$ ---- eqn 1

The solution is $x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Now , the given Quadratic Equation is $x^{2}+5 x+7=0$ ---- eqn 2

On comparing Equation (1) and Equation(2), we get

a = 1 , b = 5 and c = 7

In $x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$ , $b^2 - 4ac$ is called the discriminant of the quadratic equation

Its value determines the nature of roots

Now, here are the rules with discriminants:

1) D > 0; there are 2 real solutions in the equation

2) D = 0; there is 1 real solution in the equation

3) D < 0; there are no real solutions in the equation

Now let solve for given equation

$D= b^2 - 4ac\\\\D = 5^2 - 4(1)(7)\\\\D = 25 - 28 \\\\D = -3$

Since -3 is less than 0, this means that there are 0 real solutions in this equation.

4 0

3 years ago

How do you graph y = 5

Anarel [89]

Answer:

start at the origin (0,0) then move up 5 (Don't count the origin as the first move up). Now your point is (0,5)

Step-by-step explanation:

6 0

3 years ago

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