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Fofino [41]
3 years ago
6

3. In the following formal proof, what is the missing reason?

Mathematics
2 answers:
Lana71 [14]3 years ago
6 0

Answer:

A

Step-by-step explanation:

Start with 2x = 12, and end with x = 6.

To do that, you need to divide both sides by 2.

Answer: A

AlladinOne [14]3 years ago
3 0
The answer is A
I just know it
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Suppose that Fx) = x3 and G(x) = -2x2. Which statement best compares the
Rudiy27

Answer:

D

Step-by-step explanation:

you can just find the value of y and try some number of x

i.e. if x = 0, both of them will be 0

x = 1

G(x) result is -2

F(x) result is 1

x= -1

G(x) result will be 2

F(x) result is -1

so from these we can prove that G(x) is bigger graph than F(x) but flip vertically by y axis

8 0
3 years ago
How to solve for axis of symmetry for y=(x+2)(x-4)
lianna [129]

Answer:

x = 1

Step-by-step explanation:

you can first find the two zeroes

that would be

x + 2 = 0

x - 4 = 0

x = {-2, 4}

then you average them

-2 + 4 = 2

2 / 2 = 1

the aos is 1

5 0
2 years ago
Read 2 more answers
Can someone pls help me with this?
Hatshy [7]

Answer:

Between 1 and 3 seconds

Step-by-step explanation:

There is no change in distance ( change in y ) between 1 and 3, so she wasn't walking during that time

4 0
2 years ago
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9/20
Stella [2.4K]

<u>Question:</u>

Find the number of real number solutions for the equation. x^2 + 5x + 7 = 0

<u>Answer:</u>

The number of real solutions for the equation x^{2}+5 x+7=0 is zero

<u>Solution:</u>

For a Quadratic Equation of form : a x^{2}+b x+c=0  ---- eqn 1

The solution is x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}  

Now , the given Quadratic Equation is x^{2}+5 x+7=0  ---- eqn 2

On comparing Equation (1) and Equation(2), we get

a = 1 , b = 5 and c = 7

In x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a} , b^2 - 4ac is called the discriminant of the quadratic equation

Its value determines the nature of roots

Now, here are the rules with discriminants:

1) D > 0; there are 2 real solutions in the equation

2) D = 0; there is 1 real solution in the equation

3) D < 0; there are no real solutions in the equation

Now let solve for given equation

D= b^2 - 4ac\\\\D = 5^2 - 4(1)(7)\\\\D = 25 - 28 \\\\D = -3

Since -3 is less than 0, this means that there are 0 real solutions in this equation.

4 0
3 years ago
How do you graph y = 5
Anarel [89]

Answer:

start at the origin (0,0) then move up 5 (Don't count the origin as the first move up). Now your point is (0,5)

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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