One can know if an equation is extraneous if after plugging it in the original equation, it shows a false meaning or the value is undefined.
<h3>What is an extraneous equation?</h3>
It should be noted that an extraneous equation means a root of a transformed equation that isn't the root of the original equation due to the fact that it's excluded from the domain of the original equation.
In this case, one can know if an equation is extraneous if after plugging it in the original equation, it shows a false meaning or the value is undefined.
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The answer is: " 60° " .
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" m∠A = 60° " .
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Explanation:
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Note: All triangles, by definition, have 3 (three) sides and 3 (three angles).
The triangle shown (in the "image attached") has three EQUAL side lengths. Therefore, the triangle shown is an "equilateral triangle" and has 3 (three) equal angles, as well.
All triangles by, definition, have 3 (three) angles that add up to "180° " .
Since each of the 3 (three) angles is equal; and the three angles are:
"∠A" , "∠B" , and "∠C" ;
We can find the measure of "∠A" ; denoted as: "m∠A" ; as follows:
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m∠A = 180° ÷ 3 = 60° .
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The answer is: " 60° " .
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m∠A = " 60° " .
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Answer
Arc EF = 52°
Arc HD = 142°
Angle HGF = 128°
Explanation
To solve for the unknown angles, we need to first solve for x
To do that, we need to first note that the sum of angles on a straight line is 180°
So,
Angle HCG + Angle HCD = 180° (Sum of angles on a straight line)
Angle HCG = 2x
Angle HCD = 6x + 28°
Angle HCG + Angle HCD = 180°
2x + 6x + 28° = 180°
8x + 28° = 180°
8x = 180° - 28°
8x = 152°
Divide both sides by 8
(8x/8) = (152°/8)
x = 19°
Angle HCG = 2x = 2 (19°) = 38°
Angle HCD = 6x + 28° = 6(19°) + 28° = 142°
So, we can solve for the rest now
Arc EF = Angle ECF
= 90° - Angle ECD
Angle ECD = Angle HCG = 38° (Vertically opposite angles are equal)
Arc EF = Angle ECF
= 90° - Angle ECD
= 90° - 38°
= 52°
Arc HD = Angle HCD = 142°
Angle HGF = Angle HCG + Angle GCF = 38° + 90° = 128°
Hope this Helps!!!
