Consider the table of the powers of 8.

? Don't Send links, don't Write random things and get the points for free.

alekssr [168]

Answer:

$V = 1847.26\ ft^3$

Step-by-step explanation:

Step 1: Determine the volume

$V=\pi r^2h$

$V = \pi *(7\ ft)^2 * (12\ ft)$

$V = \pi *49\ ft^2 * 12\ ft$

$V = \pi * 588\ ft^3$

$V = 1847.26\ ft^3$

Answer: $V = 1847.26\ ft^3$

6 0

2 years ago

PLZ ANSWER !!! QUICKLY

a_sh-v [17]

The answer is 560in^3

4 0

3 years ago

As shown, a section of a roller coaster track (figure 3) follows the form of y=(2/3)x1.5. locate the centroid x? of the track be

LiRa [457]

F(x)=(2/3)x^1.5

The centroid position along the x-axis can be obtained by
integrating the function * x to get the moment about the y-axis,
then divide by the area of the graph,
all between x=0 to x=3.5m.

Expressed mathematically,
x_bar=(∫f(x)*x dx )/(∫ f(x) dx limits are between x=0 and x=3.5m
=15.278 m^3 / 6.1113 m^2
=2.500 m

3 0

3 years ago

Ok whoever answers this correct will get 100 brainly points

Snezhnost [94]

Answer:

We are given an area and three different widths and we need to determine the corresponding length and perimeter.

The first width that is provided is 4 yards and to get an area of 100 we need to multiply it by 25 yards. This would mean that our length is 25 yards and our perimeter would be 2(l + w) which is 2(25 + 4) = 58 yards.

The second width that is given is 5 yards and in order to get an area of 100 yards we need to multiply by 20 yards. This would mean that our length is 20 yards and our perimeter would be 2(l + w) which is 2(20 + 5) = 50 yards.

The final width that is given is 10 yards and in order to get an area of 100 yards we need to multiply by 10. This would mean that our length is 10 yards and our perimeter would be 2(l + w) which is 2(10 + 10) = 40 yards.

Therefore the field that would require the least amount of fencing (the smallest perimeter) is option C, field #3.

Hope this helps!

3 0

2 years ago

Read 2 more answers

98 Points !! These are follow up according to previous question that had been answered for me. Help would be appreciated ! :))

IgorLugansk [536]

That's a copy of the figure from the other post; I didn't look at the answer.

We have Start(0,0)

$A(-16.55\cos 25, -16.55 \sin 25)$

$B=A+(5 \cos 53, 5 \sin 53)$

$C=B+(20,0)$

$C=(-16.55\cos 25 + 5 \cos 53+20, -16.55 \sin25 - 5 \sin 53)$

$C \approx (8.00968, -10.9875) \approx(8,-11)$

Your team takes the direct path at a constant speed of 6 miles per hour.

Our team. $T=\sqrt{8^2+11^2}/6 = 2.27 \textrm{ hours}$

Team Red follows the riddle and travels at 8 mph from Start to Post A, 9 mph from Post A to Post B, and 11 mph from Post B to Finish.

$T=16.55/8 + 5/9 + 20/11 = 4.44 \textrm{ hours}$

Team Blue follows the riddle and travels at a constant speed of 10 mph.

 $T=(16.55 + 5 + 20)/10 = 4.155 \textrm{ hours}$

Team Yellow follows the riddle and travels at a constant speed of 11 mph, but stops at Post A for 30 minutes and stops again at Post B for another 30 minutes.

$T=(16.55 + 5 + 20)/11 + 30/60 + 30/60=4.78 \textrm{ hours}$

Winner: our team, then Blue, then Red, then Yellow

3 0

4 years ago