(3x2 + 7x + 10) - (3x2 - 12x - 10)

Mathematics

1 answer:

mote1985 [20]3 years ago

6 0

Answer:

19x + 20

I have a picture of my work here for an explanation

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Write an equation of a line (in standard form) that has the same slope as the line 3x-5y=7 and the same y-intercept as the line

Vanyuwa [196]

Answer:

$3x-5y=-20$

Step-by-step explanation:

We can write the equation of a line in 3 different forms including slope intercept, point-slope, and standard depending on the information we have. We have two standard form equations which we will get a slope and a y-intercept from. We will convert each to slope intercept form to get the information. We will then write a new slope-intercept equation and convert to standard form.

3x-5y=7 has the same slope as the line. Let's convert.

$3x-5y=7\\3x-3x-5y=7-3x\\-5y=7-3x\\\frac{-5y}{-5}=\frac{7-3x}{-5} \\$

$y=\frac{3}{5}x -\frac{7}{5}$

The slope is $m=\frac{3}{5}$ .

2y-9x=8 has the same y-intercept as the line. Let's convert.

$2y-9x=8\\2y-9x+9x=8+9x\\2y=8+9x\\\frac{2y}{2}=\frac{8+9x}{2}$

$y=\frac{8}{2}+\frac{9x}{2} \\y=4+\frac{9}{2}x$

The y-intercept is 4.

We take $m=\frac{3}{5}$ and b=4 and substitute into y=mx+b.

$y=\frac{3}{5}x+4$

We now convert to standard form.

$-\frac{3}{5}x+y=\frac{3}{5}x-\frac{3}{5}x+4\\-\frac{3}{5}x+y=4$

For standard form we need the coefficients of x and y to be not zero or fractions. We need integers but the coefficient of x cannot be negative. So we multiply the entire equation by -5 to clear the denominators.

$-5(-\frac{3}{5}x+y=4)\\3x-5y=-20$