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andreev551 [17]
3 years ago
14

The velocity, V, of a specific object being dropped from a particular height, h, can be found by the radical function V equals t

he square root of the quantity 2 times h times a end quantity where a represents the acceleration in ft/sec2. If the acceleration due to gravity is 32.2 ft/sec2, at what height should you drop an object in order for it to have a velocity of 80 ft/sec? 5,152 feet 99.4 feet 71.8 feet 1.5 feet
Mathematics
1 answer:
Jobisdone [24]3 years ago
7 0

Answer:

20.3 ft/sec

Step-by-step explanation:

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Answer:

16.9265381881

Step-by-step explanation:

Tangent = Opposite/Adjacent.

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7 0
2 years ago
A parabola has a focus of F(2, -0.5) and a directrix of y=-1.5 P(x,y) represents any point on the parabola, while D(x, -1.5) rep
prohojiy [21]
The sketch of the parabola is attached below

We have the focus (a,b) = (2, -0.5)
The point P(x,y)
The directrix, c at y=-1.5

The steps to find the equation of the parabola are as follows

Step 1
Find the distance between the focus and the point P using Pythagoras. We have two coordinates; (2, -0.5) and (x,y).
We need the vertical and horizontal distances to find the hypotenuse (the diagram is shown in the second diagram).
The distance between the focus and point P is given by
\sqrt{ (x-a)^{2}+ (y-b)^{2} }

Step 2
Find the distance between the point P to the directrix c. It is a vertical distance between y and c, expressed as y-c

Step 3
The equation of parabola is then given as 
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(x-2)^{2}+ (y--0.5)^{2}  = (y--1.5)^{2}
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y= \frac{ x^{2} }{2} -2x+1

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Answer: Negative
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This sign flip rule does not happen if you multiply both sides by a positive number.
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Answer:

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