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andreev551 [17]
3 years ago
14

The velocity, V, of a specific object being dropped from a particular height, h, can be found by the radical function V equals t

he square root of the quantity 2 times h times a end quantity where a represents the acceleration in ft/sec2. If the acceleration due to gravity is 32.2 ft/sec2, at what height should you drop an object in order for it to have a velocity of 80 ft/sec? 5,152 feet 99.4 feet 71.8 feet 1.5 feet
Mathematics
1 answer:
Jobisdone [24]3 years ago
7 0

Answer:

20.3 ft/sec

Step-by-step explanation:

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Find the value of x. Round to the nearest tenth.
svlad2 [7]

Answer:

3.13

Step-by-step explanation:

2.1^-1.4^2 = 2.45

Square root 2.45 + 1.56

1.56 x 2= 3.13

6 0
4 years ago
you go to the movies with 5 friends. you and one of your friends each buy a bag of popcorn. the rest of your friends buy just on
vfiekz [6]
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4 years ago
Help me with this question please
notka56 [123]
The answer is C, 6 x 4 = 24!
5 0
3 years ago
Use the formula for compound interest, a P 1 i n = ^ h + , to determine how many years it will take for an investment of W10 000
Sergeu [11.5K]

The money will be triple after 15 years and 303 days.

What is compound interest?

Compound interest, also known as interest on principal and interest, is the practice of adding interest to the principal amount of a loan or deposit.

Given:

Principle (P) = $10,000

The amount will be triple.

So, Amount (A) = $30,000

Rate (r) = 7% = 0.07

The interest is compounded quarterly.

n = 4

We have to find the value of t.

Let,

A = P(1+\frac{r}{n})^n^t\\ 30000 = 10000(1+\frac{0.07}{4})^4^t\\\frac{30000}{10000} = (1 + 0.0175)^4^t\\ 3 = (1.0175)^4^t

Apply logarithm on both sides,

log(3) = log(1.0175)^4^t\\log(3) = 4t log(1.0175)\\t = \frac{log(3)}{4(log(1.0175))} \\t = \frac{0.4771212547}{4(0.0075344179)} \\t = \frac{0.4771212547}{0.0301376716} \\t = 15.83139

Hence, the money will be triple after 15 years and 303 days.

To know more about compound interest, click on the link

brainly.com/question/24274034

#SPJ4

6 0
1 year ago
Describe the congruence transformation that maps ΔABC onto ΔA′B′C′ in the given figure.
babymother [125]
<h3>Answer: Choice B</h3>

Reflection along y axis

Translation: (x,y) \to (x,y-3)  which means we shift 3 units down

===========================================================

Explanation:

Let's track point A to see how it could move to point A'.

If we were to reflect point A over the vertical y axis, then A(-4,4) would move to (4,4). The x coordinate flips in sign, but the y coordinate stays the same.

The diagram shows that A' is located at (4,1) instead of (4,4). So a y-axis reflection isn't enough to move A to A', but we can shift that reflected point three units down. That will move (4,4) to (4,1) which is exactly where we want to end up. Note how we subtract 3 from the y coordinate and x stays the same. So that explains the notation (x,y) \to (x,y-3)

Overall, this points to choice B as the final answer. If we apply these steps to points B and C, you should find that they'll land on B' and C' respectively.  Apply this to all of the points on the triangle ABC, and it will move everything to triangle A'B'C'.

7 0
3 years ago
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