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andreev551 [17]
3 years ago
14

The velocity, V, of a specific object being dropped from a particular height, h, can be found by the radical function V equals t

he square root of the quantity 2 times h times a end quantity where a represents the acceleration in ft/sec2. If the acceleration due to gravity is 32.2 ft/sec2, at what height should you drop an object in order for it to have a velocity of 80 ft/sec? 5,152 feet 99.4 feet 71.8 feet 1.5 feet
Mathematics
1 answer:
Jobisdone [24]3 years ago
7 0

Answer:

20.3 ft/sec

Step-by-step explanation:

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3(5b-1)=5<br> solve for b<br><br> 4(3y-1)=20<br> solve for y
Gnom [1K]
3(5b-1)=5
Get rid of the brackets
15b-3=5
add 3 to both sides of the equation
15b=8
divide both sides of the equation by 15
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4(3y-1)=20
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7 0
3 years ago
Graph y&lt; 1/3 c + 1/2
castortr0y [4]

<h3>The Graph you need above </h3>

<h3>Step-by-step explaination : </h3>

<h3>Combine 1/3and x.</h3>

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y-intercept: 1/2

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6 0
2 years ago
10. A group of 10 people go to see a movie. The tickets
KonstantinChe [14]
6 adults were in the group and 4 children
3 0
4 years ago
Read 2 more answers
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AVprozaik [17]
Question 10: 2/5 < 1/2
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5 0
3 years ago
M−2 over 4 =5 over 20
Ne4ueva [31]
m=3
Plug it in and it should work
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5 0
3 years ago
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