All categories

3 years ago

Please help ahh I don’t understand

Mathematics

2 answers:

Aleonysh [2.5K]3 years ago

7 0

Answer:

b. 37

Step-by-step explanation:

Use Pythagorean theorem $a^2+ b^2= c^2$

a=12in

b=35in

c=? (Spine)

$a^2+ b^2= c^2$

$12^2+35^2=c^2$

$144+1225=c^2$

$1369=c^2$

$\sqrt{1369} =c$

$37=c$

The spine is 37 in

meriva3 years ago

5 0

I think the answer is b if not i’m really sorry

You might be interested in

1.How many combinations are possible from the letters HOLIDAY if the letters are taken?

Lesechka [4]

Using the combination formula, it is found that:

1. A. 7 combinations are possible.

B. 21 combinations are possible.

C. 1 combination is possible.

2. There are 245 ways to group them.

<h3>What is the combination formula?</h3>

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by:

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Exercise 1, item a:

One letter from a set of 7, hence:

$C_{7,1} = \frac{7!}{1!6!} = 7$

7 combinations are possible.

Item b:

Two letters from a set of 7, hence:

$C_{7,2} = \frac{7!}{2!5!} = 21$

21 combinations are possible.

Item c:

7 letters from a set of 7, hence:

$C_{7,7} = \frac{7!}{0!7!} = 1$

1 combination is possible.

Question 2:

Three singers are taken from a set of 7, and four dances from a set of 10, hence:

$T = C_{7,3}C_{10,4} = \frac{7!}{3!4!} \times \frac{10!}{4!6!} = 245$

There are 245 ways to group them.

More can be learned about the combination formula at brainly.com/question/25821700

6 0

2 years ago

Change 4 5/7 and 7 into improper fractions

Elden [556K]

ANSWER:

4 5/7= 83/7

7= 7/1

4 0

3 years ago

A $104,000 selling price with $24,000 down at 81⁄2% for 25 years results in a monthly payment of

Katena32 [7]

Okay so first I am taking it that you have to subtract 24k from the 104k which brings it to 80,000.
I am also taking it that the 8.5% is suppose to be in decimal form which makes it .085%
Take the 80,000 and use the monthly payment formula, which is really easy to use.
Monthly payment should be 644.18

8 0

3 years ago

Read 2 more answers

Hurry please I need it tonight thank u so much

Lina20 [59]

It’s the 3rd option!

-5 (the bubble shaded black), the arrow going left towards -9.

Hope this helps!

4 0

2 years ago

How many ways are there to select a 5-card hand from a regular deck such that the hand contains at least one card from each suit

Snezhnost [94]

Answer:

There are 685464 ways of selecting the 5-card hand

Step-by-step explanation:

Since the hand has 5 cards and there should be at least 1 card for each suit, then there should be 3 suits that appear once in the hand, and one suit that apperas twice.

In order to create a possible hand, first we select the suit that will appear twice. There are 4 possibilities for this. For that suit, we select the 2 cards that appear with the respective suit. Since there are 13 cards for each suit, then we have ${13 \choose 2} = 78$ possibilities. Then we pick one card of all remaining 3 suits. We have 13 ways to pick a card in each case.

This gives us a total of 4*78*13³ = 685464 possibilities to select the hand.

6 0

3 years ago